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NNADVOKAT [17]
3 years ago
11

Will give Brainly list

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
7 0

Answer:

7 and 8 im pretty sure...

Step-by-step explanation:

sorry if its wrong..

ruslelena [56]3 years ago
6 0

B. Angles 1 and 2

Complementary angles are two angles that add up to 90 degrees, and Adjacent angles are two angles that are next to each other.

Out of the angles given angles 1 and 2 are the most likely answer, given their shape. (See picture below)

Have a beautiful day.

Hey.... can anybody help me with a question? "<u>If you can change one thing in your community with design, what would it be and how will it work towards racial justice?"</u>

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What is the discriminant in the quadratic equation x2 + 11x + 121 = x + 96? <br>      A. 0 B. 100 C. 20 D. 200
Maurinko [17]
Given:
x² + 11x + 121 = x + 96

First, we need to convert it into a quadratic equation.

x² + 11x - x + 121 - 96 = 0
x² + 10x + 25 = 0

a = 1 ; b = 10 ; c = 25

Quadratic formula:

x = (-b <u>+</u> (√b² - 4ac)) ÷ 2a

The discriminant is under the radical sign

discriminant ⇒ b² - 4ac ⇒ 10² - 4(1)(25) ⇒ 100 - 100 = 0

Correct answer is A. 0
7 0
3 years ago
Read 2 more answers
|2x+1|&gt;5 what is the answer​<br>solve for real numbers x.
umka2103 [35]

Answer:

see explanation

Step-by-step explanation:

Inequalities of the type | x | > a always have solutions of the form

x < - a or x > a, thus

2x + 1 < - 5 OR 2x + 1 > 5 ( subtract 1 from both sides of both inequalities

2x < - 6 OR 2x > 4 ( divide both sides of both inequalities by 2 )

x < - 3 OR x > 2

4 0
3 years ago
Average of $1.99 $3.29 and $2.45
marysya [2.9K]
What ? thats very confusing what is the question you have to give more info
5 0
3 years ago
Find the tangent plane to the given surface of f(x,y)=6- 6/5 x-y at the point (5, -1, 1). Make sure tat your final answer for th
HACTEHA [7]

Answer:

Required equation of tangent plane is z=\frac{6}{5}(x-5y-11).

Step-by-step explanation:

Given surface function is,

f(x,y)=6-\frac{6}{5}(x-y)

To find tangent plane at the point (5,-1,1).

We know equation of tangent plane at the point $(x_0,y_0,z_0)[/tex] is,

z=f(x_0,y_0)+f_x(x_0,y_0)(x-x_0)+f_y(x_0,y_0)(y-y_0)\hfill (1)

So that,

f(x_0,y_0)=6-\frac{6}{5}(5+1)=-\frac{6}{5}

f_x=-\frac{6}{5}y\implies f_x(5,-1,1)=\frac{6}{5}

f_y=-\frac{6}{5}x\implies f_y(5,-1,1)=-6

Substitute all these values in (1) we get,

z=\frac{6}{5}(x-5)-6(y+1)-\frac{6}{5}

\therefore z=\frac{6}{5}(x-5y-11)

Which is the required euation of tangent plane.

4 0
3 years ago
Someone plz help I already know the answer put how can I put the diagram can you guys help me can u put the picture how u did it
Oliga [24]

Answer:

therws this random chart from the internet, I think that's what they want, but not sure

8 0
2 years ago
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