Answer:
e
Explanation:
i took it myself and got it right
Given Information:
Angular displacement = θ = 51 cm = 0.51 m
Radius = 1.8 cm = 0.018 m
Initial angular velocity = ω₁ = 0 m/s
Angular acceleration = α = 10 rad/s
²
Required Information:
Final angular velocity = ω₂ = ?
Answer:
Final angular velocity = ω₂ = 21.6 rad/s
Explanation:
We know from the equations of kinematics,
ω₂² = ω₁² + 2αθ
Where ω₁ is the initial angular velocity that is zero since the toy was initially at rest, α is angular acceleration and θ is angular displacement.
ω₂² = (0)² + 2αθ
ω₂² = 2αθ
ω₂ = √(2αθ)
We know that the relation between angular displacement and arc length is given by
s = rθ
θ = s/r
θ = 0.51/0.018
θ = 23.33 radians
finally, final angular velocity is
ω₂ = √(2αθ)
ω₂ = √(2*10*23.33)
ω₂ = 21.6 rad/s
Therefore, the top will be rotating at 21.6 rad/s when the string is completely unwound.
Base in your questions that ask what cause the bright lines seen in the emission spectrum and i think the best answer to that is the H2 gas is used when protons was heated so the electron absorb all the photons and get exited and resulted by given of a light.
35 protons are present in an element whose atomic number is 35.
<u>Explanation:
</u>
In an atom of an element, the number of protons = atomic number
Number of protons = number of electrons
Mass Number = number of protons + number of neutrons
Hence, an atom with atomic number 35 will have 35 protons.
Answer:
.D)The Vector sum of the linear momenta of the fragments must be zero.
Explanation:
.D)The Vector sum of the linear momenta of the fragments must be zero.
This statement is true. This is so because no external force is acting on the masses. The motion is created by internal force so momentum of fragments will be conserved.
A) this statement is false because kinetic energy was zero in the beginning ( the bomb was stationary in the beginning )
B ) This statement is false because it violates the law of conservation of momentum .( it does not violates only when all the fragments have equal mass )
C ) This statement is zero because kinetic energy is not a vector quantity so two kinetic energy when added can not sum up to zero.
