2 years ago

11) mWhich of the following sets of three units are all metric measurements

Physics

1 answer:

Sedbober [7]2 years ago

5 0

Answer:

Answer is B.

Explanation:

I hope it's helpful!

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Two particles having charges of 0.440 nC and 11.0 nC are separated by a distance of 1.80 m . 1) At what point along the line con

Harlamova29_29 [7]

Answer:

a) 0.3 m

b) r = 0.45 m

Explanation:

given,

q₁ = 0.44 n C and q₂ = 11.0 n C

assume the distance be r from q₁ where the electric field is zero.

distance of point from q₂ be equal to 1.8 -r

now,

E₁ = E₂

$\dfrac{K q_2}{(1.8-r)^2} = \dfrac{K q_1}{r^2}$

$(\dfrac{1.8-r}{r})^2= \dfrac{q_2}{q_1}$

$\dfrac{1.8-r}{r}= \sqrt{\dfrac{11}{0.44}}$

1.8 = 6 r

r = 0.3 m

<h3>b) zero when one charge is negative.</h3>

let us assume q₁ be negative so, distance from q₁ be r

from charge q₂ the distance of the point be 1.8 +r

now,

E₁ = E₂

$\dfrac{K q_2}{(1.8+r)^2} = \dfrac{K q_1}{r^2}$

$(\dfrac{1.8+r}{r})^2= \dfrac{q_2}{q_1}$

$\dfrac{1.8+r}{r}= \sqrt{\dfrac{11}{0.44}}$

1.8 =4 r

r = 0.45 m

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3 years ago

A submarine sends a signal and receives an echo after 5 seconds. Calculate the speed of sound if distance of object from submari

Reil [10]

$speed = distance \div time$
Since the sound travels from the submarine to the object AND back, it actually travelled 3625x2=7250m.

$7250 \div 5 = 1450$
Speed of sound: 1450m/s

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3 years ago

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If the velocity of a body varied uniformly from 10 m s-1 to 25 m s-1

BaLLatris [955]

Answer:

3m/s2

Explanation:

a = (v-u) / t

a = (25 - 10) / 5

a = 15 / 5

a = 3

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1 year ago

The free body diagram represents Silly Sally hanging from a trapeze bar. Sally weighs 660 Newtons. What is the force in each of

Y_Kistochka [10]

A) 330 N

Explanation: Her weight must be evenly distributed between the chains (assuming they are at an even level), so you divide 660 by 2 and get 330

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3 years ago

What is the student's kinetic energy at the bottom of the hill if he is moving

soldi70 [24.7K]

Answer:

KE = 10530 J or 10.53 KJ

Explanation:

The formula for kinetic energy is KE = 1/2 mv^2

Let's apply the formula:

KE = 1/2 mv^2

KE = 1/2 (65kg) (18m/s)^2

KE = 10530 J or 10.53 KJ

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2 years ago