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xz_007 [3.2K]
2 years ago
8

A car is traveling at a velocity of 22 m/s when the driver puts on the brakes

Physics
1 answer:
Brums [2.3K]2 years ago
8 0

The car’s velocity at the end of this distance is <em>18.17 m/s.</em>

Given the following data:

  • Initial velocity, U = 22 m/s
  • Deceleration, d = 1.4 m/s^2
  • Distance, S = 110 meters

To find the car’s velocity at the end of this distance, we would use the third equation of motion;

Mathematically, the third equation of motion is calculated by using the formula;

V^2 = U^2 + 2dS

Substituting the values into the formula, we have;

V^2 = 22 + 2(1.4)(110)\\\\V^2 = 22 + 308\\\\V^2 = 330\\\\V^2 = \sqrt{330}

<em>Final velocity, V = 18.17 m/s</em>

Therefore, the car’s velocity at the end of this distance is <em>18.17 m/s.</em>

<em></em>

Read more: brainly.com/question/8898885

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Hello there.

1.986*10^6

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3 years ago
0.22 L of pancake syrup has a mass of 33 g.
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Answer:

a. 150 g/L

b. 75 g

c. 120 mL

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b. 33g/0.22L=150 g/L

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2 years ago
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3 years ago
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Therefore,
\frac{ P_{1}  V_{1} }{ T_{1} } =  \frac{ P_{2}  V_{2} }{ T_{2} }

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V1 = 85 ml
T1 = 90°C = 363.15 K
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T2 = ?

Substituting;
T_{2} =  \frac{ P_{2}  V_{2}  T_{1} }{ P^{1}  V^{1} } =  \frac{850*350*363.15}{1200*85} = 1059.19 K = 786.04 °C
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Kobotan [32]

Answer: The speed will be  30 m/s .

Explanation:

Given: Initial velocity of the car: u = 0 m/s

Constant Acceleration: a = 5 m/s²

Time: t= 6 seconds

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Formula:  v = u+at

Substitute values in the formula, we get

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i.e. Final velocity = 30 m/s

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