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aksik [14]
3 years ago
7

A rock is dropped into a canyon that is 0.3 km deep. Determine the time it takes the rock to hit the bottom of the canyon?

Physics
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

rock of mass m is dropped to the ground from a height h. A second rock, with mass 2m, is dropped from the same height. When the second rock strikes the ground, what is its kinetic energy? (a) Twice that of the first rock, (b) four times that of the first rock, (c) same as that of the first rock, (d) half as much as that of the first rock, (e) impossible to determine.

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Earth is slightly closer to the sun in january than in july. How does the area swept out by earth’s orbit around the sun during
Anna007 [38]

This is because both areas are the same.

8 0
3 years ago
(a) If an object travels along a line with constant velocity −24 ms, then the general formula for the position of the object is_
postnew [5]

Mathematically we know that the position is the integral of the velocity as a function of time, that is, the general formula for determining the position as a function of velocity would be given by

x(t) = x_0 +\int_0^t vdt

Here

x_0 represents the initial position, and the integral, the position with respect to the speed of the object within a certain time

Replacing and considering that there is no starting position,

v(t) = -24

x (t) = -24 \int dt

x(t) = -24t+C

7 0
3 years ago
A yellow train of mass 100 kg is moving at 8 m/s towards an orange train of mass 200 kg traveling on the opposite direction on t
vladimir1956 [14]
Mass of yellow train, my = 100 kg

Initial Velocity of yellow train, = 8 m/s

mass of orange train = 200 kg

Initial Velocity of orange train = -1 m/s (since it moves opposite direction to the yellow train, we will put negative to show the opposite direction)

To calculate the initial momentum of both trains, we will use the principle of conservation of momentum which

The sum of initial momentum = the sum of final momentum


Since the question only wants the sum of initial momentum,

(100)(8) + (200)(-1) = 600 m/s

8 0
2 years ago
A naked, male corpse was found at 8AM on Tuesday, July 9.The air temperature wasalready 26.7˚C (81˚F). The body exhibited some s
Slav-nsk [51]

Answer:

x = 9.87 hours ago.

Further explanation is present below.

Explanation:

Data given:

Air Temperature = 26.7°C (81°F)

Body temperature = 34.4°C (93.9°F)

We are given that, Livor mortis was absent. Secondly, The body exhibited some stiffness in the face and eyelids.

So, it can be concluded that, body must have died recently, as Livor mortis was absent plus the presence of stiffness in the face and eyelids. Furthermore,

The normal body temperature = 37°C

Body temperature in our case = 34.4° C

Difference = 37 -34.4 = 2.6°C

And Air temperature = 26.7°C

Which is a very low difference, in addition, it has not acquired the air temperature so, all this evidence certifies that body died recently.

Now, we have to calculate, how recently it died.

Formula:

0.78 . x = difference of body temperature and air temperature

Where, x = number of hours = time required,

0.78 . x = (34.4 - 26.7)

0.78 . x = 7.7

x = 7.7/0.78

x = 9.87 hours ago.

It means that, naked male corpse was died 9.87 hours ago.

Now, we are asked to find out clothing on the body had made a difference or not.

So, Yes it would definitely make a difference. As body would have more warmer than being naked. and it would result in a calculation of a different time of death. (body temperature would have > 34.4°C)

3 0
3 years ago
Which can be used as a lever ?
Svet_ta [14]
B long board because of the length
7 0
3 years ago
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