Answer:
The value is 
Explanation:
From the question we are told that
The mass of the shed is 
The length of the rope is 
The angular speed of the shed is 
Generally the force exerted on the shed is mathematically represented as
=> 
=>
Answer:
The velocity of the object at the bottom is, v = 17.15 m/s
Explanation:
Given data,
The initial velocity of the object, u = 0
The height of the hill, h = 15 m
Let 'S' be the distance of the slope of the hill and 'Ф' be the slope of the hill formed with the ground.
The acceleration due to gravity component along the slope is given by,
a = g Sin Ф
The distance of the slope since height 'h' of the hill is given,
s = h / Sin Ф
Using the III equation of motion,
v² = 2 as (∵ u = 0)
v² = 2 x g Sin Ф x h / Sin Ф
= 2 gh
Therefore,
<em> v = √(2gh)</em>
Substituting the given values,
v = √(2x9.8x15)
= 17.15 m/s
Hence, the velocity of the object at the bottom is, v = 17.15 m/s
go to doc micstuffens world
Hello,
I hope you're having a great day!
Here's what I got to question A and B
a) Fs(max)=(0.560)(88.9N)=49.8N Fy=88.9N-49.8N=39.1N Fx=(39.1N)/(cos(40))=51.0N sqrt{39.1^2+51.0^2}=F
F=64.3N
b) 88.9N +49.8 N=138.7N=Fy Fx=(138.7N)/(cos(40))=181.06N sqrt{138.7^2+181.06^2}=F
F=228N
Answer:
i think your answer is this: the objects have no interactive with each other.
Explanation:
if you think about it tissue paper doesn't really have a static electrical charge if it does it is very weak so therefore cannot really attract or repel anything.
