In formation of a Type II Binary Compound, the metal atom present is<span>
NOT</span> found in either Group 1 or Group 2 on the periodic table. For the choices, Ba is under Group 2 on the periodic table, which makes it the atom not involved in formation of type II compounds. The answer is B.
Answer:
Ni(s) + H₂O(l) -------------> [Ni(H₂O)₆]²⁺
Explanation:
Data Given:
Reactants:
Ni(s) + H₂O(l)
Product = ?
Solution:
Names of the Reactants
Ni = Nickel
H₂O = water
Reaction:
Normally nickel directly does not react with water under normal condition. But indirectly in acidic or neutral condition it form complex ion.
For this it first dissolve slowly in dilute acid, in this reaction it liberate Ni²⁺ ions these nickel ions form light green complex ions in aqueous solution.
Ni(s) + H₂SO₄(aq) -------> Ni²⁺(aq) + SO₄²⁻(aq) + H₂
This is a type of complex formation in which Nickel react with water and produced a light green color new complex ion or product.
Complete reaction is as under
Ni(s) + H₂O(l) -------------> [Ni(H₂O)₆]²⁺
Balance Reaction:
Ni(s) + 6 H₂O(l) -------------> [Ni(H₂O)₆]²⁺
So.
by this reaction one product is formed that is [Ni(H₂O)₆]²⁺ named as hexaqua nickel ion
Freezing the substance and condensing it will not increase the entropy of a substance. In fact, dissolving the substance into water is the only way to increase the entropy of a certain substance. The entropy increases because it diversify with each other.
Answer:The number of valence electrons in an atom increases down the group due to the increase in energy levels at progressively lower levels. The electrons are progressively further from the nucleus; therefore, the nucleus and the electrons are not as attracted to each other. An increase in shielding is observed.
Explanation: Read this and you'll find your answer~! I hope i helped you~! Have an GREAT day~! <\3
First, let's explain the variables. F means force, m means mass, and a means acceleration. F is measured in Newotns [N], mass is measured in kilograms [kg], and acceleration in measured in meters per squared second [m/s²].
Now let's mover on the first problem.
Given
m = 1000 kg
a = 3 m/s²
According to the second law of Newton, the force is equal to the acceleration multiplied by the mass.
The answer is 3000 N.
The second problem is smiliar.
Given
m = 70 kg
F = 250 N
We use the same formula from before, and use a bit of algebra to adapat it to our needs.
The answer is 24 1/7 s/m^2.
