Answer:
The moment of inertia of the system is
Explanation:
From the question we are told that
The mass of the platform is
The radius of the platform is r = 1.95 m
The mass of the person is
The position of the person from the center is
The mass of the dog is
The position of the dog from the center is
Generally the moment of inertia of the platform with respect to its axis is mathematically represented as
The moment of inertia of the person with respect to the axis is mathematically represented as
The moment of inertia of the dog with respect to the axis is mathematically represented as
So the moment of inertia of the system about the axis is mathematically evaluated as
=>
substituting values
Answer:
C. 1.04%
Explanation:
The following information has been provided;
Actual density of gold; 19.3 g/cm^3
Observed/measured density of gold; 19.1 g/cm^3
The formula for percent error is given as;
((actual value - observed value)/actual value)) * 100
The percent error of the student's measurement is thus 1.04%
Answer:
Explanation:
Using second degree taylor polynomials
let be position function and set
where S(0) is the initial position
Then and
we have ,
so
b.) yes
R = 0.407Ω.
The resistance R of a particular conductor is related to the resistivity ρ of the material by the equation R = ρL/A, where ρ is the material resistivity, L is the length of the material and A is the cross-sectional area of the material.
To calculate the resistance R of a wire made of a material with resistivity of 3.2x10⁻⁸Ω.m, the length of the wire is 2.5m and its diameter is 0.50mm.
We have to use the equation R = ρL/A but first we have to calculate the cross-sectional area of the wire which is a circle. So, the area of a circle is given by A = πr², with r = d/2. The cross-sectional area of the wire is A = πd²/4. Then:
R =[(3.2x10⁻⁸Ω.m)(2.5m)]/[π(0.5x10⁻³m)²/4]
R = 8x10⁻⁸Ω.m²/1.96x10⁻⁷m²
R = 0.407Ω