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rusak2 [61]
3 years ago
7

What is the total mass of chlorine

Physics
1 answer:
tamaranim1 [39]3 years ago
4 0
One mole of chlorine is equal to 35.453 grams, while one atom is 35.453 AMU
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A ball is shot straight up from the surface of the earth with an initial speed of 19.6 m/s. Neglect any effects due to air resis
Pavel [41]

Answer:

4 s

Explanation:

u = 19.6 m/s, g = 9.8 m /s^2

Let the time taken to reach the maximum height is t.

Use first equation of motion.

v = u + at

At maximum height, final velocity v is zero.

0 = 19.6 - 9.8 x t

t = 19.6 / 9.8 = 2 s

As the air resistance be negligible, is time taken to reach the ground is also 2 sec.

So, total time taken be the ball to reach at original point = 2 + 2 = 4 s

5 0
3 years ago
Which one describes how much matter an object contains, using SI units?
ahrayia [7]
Si units or Systeme' de Internationale' is a widely adopted unit system in measuring basic and derived dimensions In this case, the SI units here are kilograms, meter and seconds. Pounds is an English unit. mass is the measure of <span>how much matter an object contains, hence the answer is A. 43 kg.</span>
5 0
3 years ago
Read 2 more answers
Calculate the RMS voltage of the following waveforms with 10 V peak-to-peak:
Deffense [45]

Answer:

a) T=0.01s

b) T=0.001s

c) T=0.00001s

Explanation:

From the question we are told that:

Given Frequencies

a. 100 Hz,

b. 1 kHz,

c. 100 kHz.

Generally the equation for Waveform Period is mathematically given by

T=\frac{1}{f}

Therefore

a)

For

T=100 Hz

T=\frac{1}{100}

T=0.01s

b)

For

F=1kHz

T=\frac{1}{1000}

T=0.001s

c)

For

F=100kHz

T=\frac{1}{100*100}

T=0.00001s

6 0
3 years ago
A proposed communication satellite would revolve around the earth in a circular orbit in the equatorial plane at a height of 358
aleksandr82 [10.1K]

Answer:

Period is 86811.5 seconds.

Explanation:

{ \boxed{ \bf{T {}^{2} =  (\frac{4 {\pi}^{2} }{GM}) {r}^{3}   }}}

{ \tt{T {}^{2}  =  \frac{4 {(3.14)}^{2} }{(6.6 \times  {10}^{ - 11} ) \times (5.98 \times  {10}^{24} )} \times  {((35880\times  {10}^{3}) } + (6370 \times  {10}^{3} )) {}^{3}   }} \\  \\ { \tt{T {}^{2}  =  7.54 \times {10}^{9} }} \\ { \tt{T =  \sqrt{7.54 \times  {10}^{9} } }} \\ { \tt{T = 86811.5 \: seconds}}

6 0
3 years ago
What is the displacement of the armadillo between 0s and 24s ?
Ann [662]

Answer:

Displacement: 6 meters

Distance: 24 meters

Explanation:

4 0
2 years ago
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