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vivado [14]
3 years ago
9

Help me please !!! I need this question as soon as possible help !!!!!!!

Chemistry
2 answers:
IRISSAK [1]3 years ago
8 0

Answer:land, crust, magma and core

Explanation:

hammer [34]3 years ago
6 0
Land, crust, magma, outer core, inner core
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At standard pressure, the total amount of heat required to completely vaporize a 100. gram sample of water at its boiling point
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We know that the heat of vaporization of water is 2260 J/g. So 100 gram sample of water being completely vaporized needs 2260*100=2.26*10^5 J. So the answer is (4).
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Calculate the mass of each product formed when 84.3 g of silver sulfide reacts with excess hydrochloric acid: ag2s(s) + hcl(aq)
oee [108]

Answer:

              48.75 g of AgCl

               11.60 g of H₂S

Solution:

The Balance Chemical Equation is as follow,

                                     Ag₂S  +  HCl     →     AgCl  +  H₂S

<u>Calculate amount of AgCl produced</u><u>,</u>

According to equation,

                247.8 g (1 mol) of Ag₂S produces  =  143.32 g (1 mol) of AgCl

So,

                         84.3 g of Ag₂S will produce  =  X g of AgCl

Solving for X,

                      X  =  (84.3 g × 143.32 g) ÷ 247.8 g

                      X  =  48.75 g of AgCl

<u>Calculate amount of H</u><u>₂</u><u>S produced</u><u>,</u>

According to equation,

                247.8 g (1 mol) of Ag₂S produces  =  34.1 g (1 mol) of H₂S

So,

                         84.3 g of Ag₂S will produce  =  X g of H₂S

Solving for X,

                      X  =  (84.3 g × 34.1 g) ÷ 247.8 g

                      X  =  11.60 g of H₂S

6 0
3 years ago
Calculate the quantity of energy required to change 8.22 mol of liquid water to steam at 100oc. the molar heat of vaporization o
Ainat [17]
Since  the water  is  at  100 degrees  then   it take  40.6 kj/mol   to  change 1  mole of  water at 100 degrees into  steam at  100  degrees
  the  moles  of water  8.22mol
since  one  mole  take 40.6kj/mol   8.22mol  will  be  =
8.22mol  x  40.6 kj/mol =333.732  kj
 
4 0
3 years ago
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