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Finger [1]
3 years ago
9

Please help on my test

Chemistry
1 answer:
Alisiya [41]3 years ago
5 0

Answer:

C

Explanation:

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If you have 10.0 g of hydrogen and 5.0 g of oxygen, what mass of the excess reagent remains after the completion of the reaction
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mass Hydrogen=9.376 g

<h3>Further explanation </h3>

Reaction

2H₂+O₂⇒2H₂O

mass H₂ = 10 g

mol H₂(MW=2 g/mol) :

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mass O₂=5 g

mol O₂(MW=32 g/mol) :

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O₂ limiting reactant

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 2 x 0.156 = 0.312

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<h3 />

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3 years ago
At which temperature and pressure would a sample of helium behave most like an ideal gas?
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Here we have to get the temperature and pressure at which helium gas mostly behaves as ideal gas.

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Read 2 more answers
Sodium carbonate reacts with nitric acid to form sodium nitrate, carbon dioxide, and water according to the balanced reaction be
Ne4ueva [31]

<u>Answer:</u> The mass of sodium carbonate reacted is 0.205 g.

<u>Explanation:</u>

To calculate the moles of a solute, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

We are given:

Volume of nitric acid = 25 mL = 0.025 L   (Conversion factor: 1 L = 1000 mL)

Molarity of the solution = 0.155 moles/ L

Putting values in above equation, we get:

0.155mol/L=\frac{\text{Moles of nitric acid}}{0.025L}\\\\\text{Moles of nitric acid}=0.003875mol

For the given chemical reaction:

Na_2CO_3+2HNO_3\rightarrow H_2CO_3+2NaNO_3

By Stoichiometry of the reaction:

If 2 moles of nitric acid reacts with 1 mole of sodium carbonate.

So, 0.003875 moles of nitric acid will react with \frac{1}{2}\times 0.003875=0.0019375moles of sodium carbonate.

To calculate the mass of sodium carbonate, we use the equation:

Molar mass of sodium carbonate = 105.98 g/mol

Moles of sodium carbonate = 0.0019375 moles

Putting values in above equation, we get:

0.0019375mol=\frac{\text{Mass of sodium carbonate}}{105.98g/mol}\\\\\text{Mass of sodium carbonate}=0.205g

Hence, the mass of sodium carbonate reacted is 0.205 g.

3 0
4 years ago
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