Answer:
I believe that it is the 2nd option.
Explanation:
My reasonings are because C4H10O has 7 isomers. In which 4 are alcohol and the other 3 are ether.
The first option is ethers, specifically ethoxyethane.
The third option is ethers, specifically 1-methoxypropane.
The fourth option is an alcohol, specifically 1- butanol.
Therefore, leads us to the 2nd option that it is NOT an isomer of C4H10O
Answer: The correct name for the compound
is, Dicarbon triiodide.
Explanation:
is a covalent compound because in this compound the sharing of electrons takes place between carbon and iodine.. Both the elements are non-metals. Hence, it will form covalent bond.
The naming of covalent compound is given by:
The less electronegative element is written first.
The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.
If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.
Hence, the correct name for the compound
is, Dicarbon triiodide..
Force= mass•acceleration
Force=800•5
Force=4000 N
Answer: Hello your question lacks some details below is the complete question
answer :
Numerator = CH₃OH
Denominator = (CO ) ( H₂)²
Explanation:
CO + 2H₂ ⇄ CH₃OH ( formation of methanol )
hence for the equilibrium constant Kc
Numerator = CH₃OH
Denominator = (CO ) ( H₂)²
<u><em>Placing into the Bin </em></u>
Numerator : CH₃OH
Denominator : (CO ) ( H₂)²
Not Used : ( CO )² , H₂ , ( CH₃OH ) ²
Answer: It is very important to know the activity tendencies of the elements. The activity tendencies tells us about whether the element is reactive or not.
In the redox-reaction where there is a need to know the oxidizing agent and reducing agent, we can know it easily from the activity tendencies. The elements lying above the reactivity series are better reducing agents.
In the substitution reactions, the activity tendencies helps us to know which element will replace the other. The element lying above in the series will replace the element lying below it.

where, N is an element that lies above in the reactivity series
M is an element that lies below in the reactivity series