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aleksklad [387]
3 years ago
8

Why does a doctor check your lymph nodes when you are sick?

Chemistry
1 answer:
AfilCa [17]3 years ago
7 0

Answer:

I think it would be B. But your lymph nodes swell when you are sick because of irritation and infection.

Explanation:

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1. What is the colour of FeSO4.7H20 crystals?How does this colour change upon heating? Give balanced
svet-max [94.6K]
<span>1. What is the colour of FeSO4.7H20 crystals?How does this colour change upon heating?

</span><span>Melanterite or FeSO4.7H20 is green in color
</span>2FeSO4 ---> Fe2O3 + SO2 + SO3<span>

2. a. What are redox reactions?
It </span><span>is a type of chemical </span>reaction<span> that involves a transfer of electrons between two species. 
</span><span>
b.Why is the reaction between MnO2 and HCl a 
redox reaction?
Because there are atoms that are reduced and are oxidized.

c.Identify the substance oxidized and the 
substance reduced in the above reaction.

</span>MnO2<span> + 4 </span>HCl<span> ---> MnCl2 + 2H2O + Cl2
</span>Mn was reduced and Cl was oxidized
5 0
3 years ago
Predict the aldol product when the following ketone undergoes self-condensation in the presence of NaOH. Do not show the dehydra
Anit [1.1K]

Answer:

β-hydroxyaldehyde (an aldol) namely 3-Hydroxy butanal.

Explanation:

When acetaldehyde is treated with dil.NaOH it undergoes self condensation as it contains alpha-hydrogen atom in its compound forming β-hydroxyaldehyde (an aldol) namely 3-Hydroxy butanal. This compound upon further heating will eliminate a molecule of water forming aldol condensation product namely Crotonaldehyde Or But-2-en-al. see the diagram attached.

5 0
3 years ago
Part III.The two reactions involved in quantitatively determining the amount of iodate in solution are: IO3-(aq) 5 I-(aq) 6 H (a
slega [8]

Answer:

\large \boxed{\math{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}

Explanation:

The I₂ is the common substance in the two equations.

(1) IO₃⁻ + 5I⁻ + 6H⁺ ⟶ 3I₂ + 3H₂O

{2) I₂ + 2S₂O₃²⁻ ⟶ 2I⁻ + S₄O₆²⁻

From Equation (1), the molar ratio of iodate to iodine is

\dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{3}{1}

From Equation (2), the molar ratio of iodine to thiosulfate is

\dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} = \dfrac{2}{1}

Combining the two ratios, we get

\text{Stoichiometric factor} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{IO}_{3}^{-}} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} \times \dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{2}{1} \times \dfrac{3}{1} = \mathbf{\dfrac{6}{1}}\\\\\text{The stoichiometric factor is $\large \boxed{\mathbf{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$}

7 0
3 years ago
Add a constant temperature when the volume of the gas is decreased what happens to its pressure
Margaret [11]

Answer:

<h2>Pressure will increase</h2>

Explanation:

At a constant temperature, the pressure of gas will increase proportional to the decrease in volume of the gas.

P1V1= P2V2

Decrease in volume result in increase in pressure as the equation has to hold true.

8 0
2 years ago
How is the food in a stomach broken down into simpler substances? What chemicals help this process?
Ksenya-84 [330]

Answer:

with the help of the juice contained in it

4 0
3 years ago
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