Answer:
The distance is 1.41 to nearest hundredth.
Step-by-step explanation:
The line y = x + 3 passes through the point (0, 3) on the yaxis.
Find the perpendicular line passing through this point:
y - 3 = -1(x + 0)
y = -x + 3
Now find the point where this line intersects the line y = x + 1:
y = -x + 3
y = x + 1
-x + 3 = x + 1
3 -1 = x + x
2x = 2
x = 1
and y = 2
So this point is (1, 2)
We require the distance between this point and (0, 3)
This = √((3-2)^2 + (0-1)^2) = √2
= 1.4142
Answer:
(0,3)
Step-by-step explanation:
graph the line using the slope and y-intercept, or two points.
the slope would be- 3/4
graphing it would be (0,3)
Answer:
x= -2, x= -10
Step-by-step explanation:
x^2 + 12x + 36 = 16
Began by setting this quadratic equation to 0. To do this, in this equation you must subtract.
x^2+12x+20=0
Next, we plug this into the quadratic formula, where a in this case is 1(there is nothing in front of x^2), b is equaled to 12(there is a 12 as the coeefficient of 12x), and c is equaled to 20.
The quadratic formula is as goes:
(-b+-(this means plus or minus)√b^2-4ac)/(2a)
After pluggin in and simplifying, the answer is x= -2 and x= -10
M = (-9 - 3) / (-5 - -2)
m = -12 / -3
m = 4
The slope is 4.
Answer:
4.6
Step-by-step explanation:
Formula: Range = highest value - lowest value
Step 1: List all the data in ascending order
1.8, 2.4, 3.5, 4.9, 5.2, 6.4
Step 2: Identify the lowest and highest number
Lowest number : 1.8
Highest number : 6.4
Step 3 : Substitute the values in the formula
Range = highest value - lowest value
6.4 - 1.8 = 4.6
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