Answer:
the answeer is definitely silicon.
Answer:
Theoretical yield of C6H10 = 3.2 g.
Explanation:
Defining Theoretical yield as the quantity of product obtained from the complete conversion of the limiting reactant in a chemical reaction. It can be expressed as grams or moles.
Equation of the reaction
C6H11OH --> C6H10 + H2O
Moles of C6H11OH:
Molar mass of C6H110H = (12*6) + (1*12) + 16
= 100 g/mol
Mass of C6H10 = 3.8 g
number of moles = mass/molar mass
=3.8/100
= 0.038 mol.
Using stoichoimetry, 1 moles of C6H110H was dehydrated to form 1 mole of C6H10 and 1 mole of water.
Therefore, 0.038 moles of C6H10 was produced.
Mass of C6H10 = molar mass * number of moles
Molar mass of C6H10 = (12*6) + (1*10)
= 82 g/mol.
Mass = 82 * 0.038
= 3.116 g of C6H10.
Theoretical yield of C6H10 = 3.2 g
Rip bro but I need the point
Answer: 3.5 moles
Explanation:
Based on Avogadro's law:
1 mole of any substance has 6.02 x 10^23 molecules
So, 1 mole of SiO4 = 6.02 x 10^23 molecules
Zmoles of SiO4 = 2.1 x 10^{24} molecules
To get the value of Z, cross multiply:
(2.1 x 10^{24} molecules x 1mole) = (6.02 x 10^23 molecules x Z moles)
2.1 x 10^{24} molecules = (6.02 x 10^23 x Z)
Z = (2.1 x 10^{24}) ➗ (6.02 x 10^23)
Z = 3.5 moles
Thus, there are 3.5 moles of SiO4.
Answer:
47%
Explanation:
MgCO₃ (s) → MgO (s) + CO₂ (g)
CaCO₃ (s) → CaO (s) + CO₂ (g)
_______________________
MgCO₃ (s) + CaCO₃ (s) → MgO (s) + CaO (s) + 2CO₂ (g)
MgO: 40.3044 g/mol
MgCO₃: 84.3139 g/mol
CaO:56.0774 g/mol
CaCO₃: 100.0869 g/mol
CO₂: 44.01 g/mol
15.42 g is the total mass of dolomite.
7.85 g is the sum of MgO and CaO produced.
This means that 7.57 g of CO₂ were produced.
44.01 g CO₂_____ 1 mol
7.57 g CO₂ _____ x
x = 0.172 mol CO₂
Considering the global reaction, we had 0.172/2 = 0.086 mol of MgCO₃ in the original sample.
1 mol MgCO₃ _______ 84.3139 g
0.086 mol MgCO₃ ___ y
y = 7.25 g
15.42 g dolomite ______ 100%
7.25 g MgCO₃ ________ z
z = 47%
