Here is the science paper

A container of oxygen has a volume of 30.0 mL and a pressure of 72.5 psi. If the pressure of the oxygen gas is reduced to 28 psi

OLga [1]

Answer:

THE NEW VOLUME OF THE OXYGEN GAS AT 28 PSI FROM 72.5 PSI IS 0.078 L.

Explanation:

Initial volume of the oxygen in the container = 30.0 mL = 30 / 000 L = 0.03 L

Initial pressure of the oxygen = 72.5 psi = 1 psi = 6890 pascal

Final pressure = 28 psi

Final volume = unknown

First convert the mL to L and since both pressures are in similar unit that is psi; there is no need converting them to pascal or other standard unit of pressure. They cancel each other out.

This question follows Boyle's equation of gas laws and mathematically it is written as:

P1 V1 = P2 V2

Re-arranging by making P2 the subject of the formula, we have:

V2 = P1 V1 / P2

V2 = 72,5 * 0.03 / 28

V2 = 2.175 /28

V2 = 0.0776 L

The new volume of the oxygen gas at a change in pressure from 72.5 psi to 28 psi is 0.078 L.

8 0

2 years ago

De acuerdo con la Ley de la Conservación de la Materia postulada por Lavoisier, ¿cuál ecuación química está balanceada? A C2H5OH

olya-2409 [2.1K]

Answer:

C C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

Explanation:

La ley de conservación de la materia implica que en una reacción química los átomos en los reactivos son iguales a la cantidad de átomos en los productos:

A C2H5OH(l) + O2(g) → CO2 + H2O

En los reactivos hay dos átomos de carbono pero en los productos solo 1. De esta manera, no cumple la ley de conservación.

B C2H5OH(l) + O2(g) → 2CO2 + H2O

En los reactivos hay 6 átomos de hidrógeno pero en los productos solo 2. No cumple la ley de conservación.

C C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

En los reactivos y productos hay: 2 átomos de carbono, 6 átomos de hidrógeno y 7 átomos de oxígeno. Cumple la ley de conservación.

D C2H5OH(l) + O2(g) → 2CO2 + 3H2O

En los reactivos hay 3 átomos de oxígeno y en los productos 7. No cumple la ley de conservación.

E 2C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

En los reactivos hay 4 átomos de carbono y en los productos solo dos. No cumple la ley de conservación.

6 0

2 years ago

You are running a rather large scale reaction where you prepare the grignard reagent phenylmagnesium bromide by reacting 210.14

almond37 [142]

Answer:

We would expect to form 7.35 moles of grignard reagent.

Explanation:

Step 1: Data given

Mass of magnesium = 210.14 grams

Volume bromobenzene = 772 mL

Density of bromobenzene = 1.495 g/mL

Molar mass of Mg = 24.3 g/mol

Molar mass of bromobenzene = 157.01 g/mol

Step 2: The balanced equation

C6H5Br + Mg ⇒ C6H5MgBr

Step 3: Calculate mass of bromobenzene

Mass bromobenzene = density bromobenzene * volume

Mass bromobenzene = 1.495 g/mL * 772 mL

Mass bromobenzene = 1154.14 grams

Step 4: Calculate number of moles bromobenzene

Moles bromobenzene = mass bromobenzene / molar mass bromobenzene

Moles bromobenzene = 1154.14g / 157.01 g/mol

Moles bromobenzene = 7.35 moles

Step 5: Calculate moles of Mg

Moles Mg = 210.14 grams /24.3 g/mol

Moles Mg = 8.65 moles

Step 6: The limiting reactant

The mole ratio is 1:1 So the bromobenzene has the smallest amount of moles, so it's the limiting reactant. It will be completely consumed ( 7.35 moles). Magnesium is in excess, There will react 7.35 moles. There will remain 8.65 - 7.35 = 1.30 moles

Step 7: Calculate moles of phenylmagnesium bromide

For 1 mole of bromobenzene, we need 1 mole of Mg to produce 1 mole of phenylmagnesium bromide

For 7.35 moles bromobenzene, we have 7.35 moles phenylmagnesium bromide

We would expect to form 7.35 moles of grignard reagent.

5 0

2 years ago

The first IE of neon (atomic number 10) is significantly higher than that of argon (atomic number 18) but significantly

lbvjy [14]

Explanation:

Different atoms binds their outermost shell electrons with different amount of energy.

The amount of energy required to remove an electron from an atom is the ionization energy.

Ionization energy measures the readiness of an atom to lose electrons.
From the given problem, we can infer that in group O the ionization energy decreases down the group.
Helium has the highest ionization energy.
Down a group on the periodic table, ionization energy decrease because:

atomic radii increases down the group.
there is an increasing shielding/screening effect of inner shell electrons on the outermost shell electrons.

Learn more:

Ionization energy brainly.com/question/2153804

#learnwithBrainly

8 0

2 years ago

PLEASE HELP URGENT ( photo included)

elena-14-01-66 [18.8K]

Answer:

B

Explanation:

4 0

2 years ago