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ludmilkaskok [199]
3 years ago
13

What is one limitation of using renewable

Physics
1 answer:
olga2289 [7]3 years ago
3 0
The answer to this question to A. The other choices are positive.
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A person has legs of length L = 1.10 m. (a) If the maximum angle between the legs during walking is ϕ = 50o , what is the person
vampirchik [111]

Answer:

a). Maximum Length L=0.929m

b). T=0.83 Hz or 1.2s

c). Longer, the effortless waling T=2.1 Hz or t=0.475s

d). t=1.2s V=0.774 \frac{m}{s}

t=0.475s V=1.95 \frac{m}{s}

Explanation:

Length legs=L=1.1m

angle=50

the step that give the person forms a triangle whose two sides are known and the angle that forms between them, then using trigonometry as the image

Divide the original triangle in two and form a right triangle so the angle is 25 and the L is hypotenuse and the opposite is the step length

a).

sin(\alpha) =\frac{op}{h}

op=h*sin(\frac{\alpha }{2})\\ op=1.1m*sin(\frac{50}{2})\\op=0.464m

Length of the step

L=0.464m*2

L=0.928m

b).

period=T

T=\frac{1}{time}=\frac{1}{t}\\ T=\frac{1}{1.2s}\\T=0.83 s^{-1}\\ T=0.83Hz

c).

T1=2\pi *\sqrt{\frac{L}{g}} \\T1=2\pi *\sqrt{\frac{1.1m}{9.8\frac{m}{s^{2}}}}\\ T1=2.1 Hz

The period is the inverse of the time of the motion so, the T1 is faster that the T because

t=\frac{1}{T1}=t= \frac{1}{2.1}=0.47s

d).

The speed is the relation between the distance with time so:

Vt=\frac{0.928m}{1.2s} \\Vt=0.773 \frac{m}{s} \\Vt=\frac{0.928m}{0.475s} \\Vt=1.953 \frac{m}{s}

3 0
3 years ago
Why dont streams flow horizontal
mylen [45]

Answer:

because

Explanation:

streasm dont flow horizontal because if it did then that would be breaking all laws of physics and we know that what goes up must com down but water cant flow upstream only down if it does flow horizontally then it would either be between two hills or in a plains

7 0
3 years ago
7. Answer each of the following questions if the student applied a 550N force to a 100kg box on the same surface. What would be
blagie [28]
F=ma
550=100a
a=550/100
a=5.5 m/s²
5 0
3 years ago
An object of mass 0.9 kg is attached to a massless string of length 3 m, and swung with 3 a tangential velocity of 3 m/s. What i
Ganezh [65]

Answer:

d

Explanation:

you have to divide by the square root and then use the factorial to multiply

5 0
2 years ago
The intensity I of light from a light​ bulb, measured in watts per square meter ​(w/m squared​), varies inversely as the square
DerKrebs [107]

Answer:

157.5W/m^2

Explanation:

We are given that

I=70w/m^2

When d=3 m

We have to find the intensity when the distance from the light bulb is 2 m away.

According to question

Intensity,I\propto\frac{1}{d^2}

I=\frac{kd^2}

Where k=Proportionality constant.

Substitute the values

70=\frac{k}{3^2}

k=70\times 3^2=630

Intensity when d=2 m

I=\frac{630}{2^2}=157.5W/m^2

6 0
3 years ago
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