All categories

3 years ago

Describe the three temperature scales used in the laboratory and in everyday life: the Fahrenheit, Celsius, and Kelvin scales.

Chemistry

1 answer:

yuradex [85]3 years ago

6 0

Explanation:

Fahrenheit Scale

Fahrenheit temperature scale is the scale which is based on:

(a) For freezing point of the water, 32 °F.

(b) For boiling point of the water, 212 °F.

With interval between two being divided into equal 180 parts.

Celsius Scale

Celsius temperature scale is the scale which is based on:

(a) For freezing point of the water, 0 °C

(b) For boiling point of the water, 100 °C.

With interval between two being divided into equal 100 parts.

Kelvin Scale 

It denotes the triple point of water where the solid, liquid, and gas phases exist in equilibrium which is at 273.16 K.

kelvin is defined as 1/ 273.16 of triple point temperature.

You might be interested in

The activation energy for a reaction is changed from 184 kJ/mol to 59.0 kJ/mol at 600. K by the introduction of a catalyst. If t

11111nata11111 [884]

Answer:

The catalyzed reaction will take 2.85 seconds to occur.

Explanation:

The activation energy of a reaction is given by:

$k = Ae^{-\frac{E_{a}}{RT}}$

For the reaction without catalyst we have:

$k_{1} = Ae^{-\frac{E_{a_{1}}}{RT}}$ (1)

And for the reaction with the catalyst:

$k_{2} = Ae^{-\frac{E_{a_{2}}}{RT}}$ (2)

Assuming that frequency factor (A) and the temperature (T) are constant, by dividing equation (1) with equation (2) we have:

$\frac{k_{1}}{k_{2}} = \frac{Ae^{-\frac{E_{a_{1}}}{RT}}}{Ae^{-\frac{E_{a_{2}}}{RT}}}$

$\frac{k_{1}}{k_{2}} = e^{\frac{E_{a_{2}} - E_{a_{1}}}{RT}$

$\frac{k_{1}}{k_{2}} = e^{\frac{59.0 \cdot 10^{3}J/mol - 184 \cdot 10^{3} J/mol}{8.314 J/Kmol*600 K} = 1.31 \cdot 10^{-11}$

Since the reaction rate is related to the time as follow:

$k = \frac{\Delta [R]}{t}$

And assuming that the initial concentrations ([R]) are the same, we have:

$\frac{k_{1}}{k_{2}} = \frac{\Delta [R]/t_{1}}{\Delta [R]/t_{2}}$

$\frac{k_{1}}{k_{2}} = \frac{t_{2}}{t_{1}}$

$t_{2} = t_{1}\frac{k_{1}}{k_{2}} = 6900 y*1.31 \cdot 10^{-11} = 9.04 \cdot 10^{-8} y*\frac{365 d}{1 y}*\frac{24 h}{1 d}*\frac{3600 s}{1 h} = 2.85 s$

Therefore, the catalyzed reaction will take 2.85 seconds to occur.

I hope it helps you!

4 0

3 years ago

What is the correct name for the cyclic alkane shown on the right?

Soloha48 [4]

Answer: C

Explanation:

4 0

3 years ago

Read 2 more answers

After using an oil-based paint, you can't clean the brush in water but you can use mineral turpentine, or white spirit. Propose

ddd [48]

Let's understand the situation

You are using an oil based paint .We know oil contains hydrocarbons means CH- bonded compound . Hydrocarbons are known as organic compounds and non polar .The thing non polar doesn't matter much but thing organic matters .

Now coming to water ,water contains OH bonding ,a lone pair is present over O which makes water polar . Although water is also known as inorganic compound.

We know that like dissolves like .In that manner Organic compounds are soluble in only organic compounds and not in inorganic compounds like water .Thus oil paint is insoluble in water as particles don't dissolve

Hence to clean the oil you need organic solvents like toulenw,spirit ,Benzyl compounds etc .

6 0

1 year ago

HOW FAST CAN YOU ANSWER

Alex777 [14]

Answer:

option "B" is correct (substance 2)

5 0

3 years ago

How do microwaves cook food? A) by using electromagnetic waves and the process of radiation B) by using forced hot air currents

Makovka662 [10]

I'm pretty sure the answer is letter A.)