First, let's count mole of 10 g Calcium Carbonate
mole = Mass / Molecular Mass
Calcium Carbonate = CaCO₃
Molecular Mass = Ar Ca + Ar C + (3 x Ar O)
Molecular Mass = 40 + 12 + (3 x 16)
Molecular Mass = 100
next
Mole of CaCO₃ = 10 gram / 100
Mole of CaCO₃ = 0,1 mol
then equal the reaction equation first
CaCO₃ + 2 HCl ==> CaCl₂ + CO₂ + H₂O (Equal)
To count the mass of carbon dioxide that produced we must know the mole of CO₂ first
we can count by coefficient comparison
mole CO₂ =
x mole CaCO₃
mole CO₂ = (1/1) x 0,1 mole
mole CO₂ = 0,1 mole
so
Mass of CO₂ = mole CO₂ x Molecular Mass of CO₂
Mass of CO₂ = 0,1 mole x (12 + (2 x 16))
Mass of CO₂ = 0,1 mole x 44
Mass of CO₂ = 4,4 g
so, mass of carbon dioxide that's produced by 10 g of calcium carbonate on reaction with chloride acid is 4,4 g.
A base in water will form hydroxide ions. This is because bases are AOH while acids are AH+. I hope this helps!
Answer:
Volume of solution = 80.5 mL
Explanation:
Given data:
Molarity of solution = 4.50 mol/L
Mass of ethanol = 16.7 g
Volume of solution = ?
Solution:
Volume will be calculated from molarity formula.
Molarity = number of moles / volume in L
Number of moles:
Number of moles = mass/molar mass
Number of moles = 16.7 g/ 46.07 g/mol
Number of moles = 0.3625 mol
Volume of solution:
Molarity = number of moles / volume in L
4.50 mol/L = 0.3625 mol / volume in L
Volume in L = 0.3625 mol /4.50 mol/L
Volume in L = 0.0805 L
Volume in mL:
0.0805 L ×1000 mL/1 L
80.5 mL
Answer:Rocket is lauched for first one, Second one is the wagon one and third one is seabelt impact.
Explanation:
The vapor molecules have greater KE than the liquid ones have. That"s how they break free of the liquid and waft away.