Answer:
265 mL is the new volume for the gas
Explanation:
We decompose the Ideal Gases Law in order to find the answer of this question: P . V = n . R . T
We can propose the formula for the 2 situations, where n remains constant.
R refers to 0.082 L.atm/mol.K which is physic constant.
We convert the temperature to Absolute value:
67.5°C + 273 = 340.5 K
80°C + 273 = 353 K
We convert the volume to L → 242.2 mL . 1 L/1000 mL = 0.2422 L
We convert the pressure values to atm:
882 Torr . 1 atm/ 760 Torr = 1.16 atm
840 Torr . 1atm / 760 Torr = 1.10 atm
P₁. V₁ / T₁ = P₂ . V₂ / T₂ → Let's replace data:
1.16 atm . 0.2422L / 340.5K = 1.10 atm . V₂ / 353 K
(1.16 atm . 0.2422L / 340.5K) . 353K = 1.10 atm . V₂
V₂ = 0.291 L.atm / 1.10 atm → 0.2647 L ≅ 265 mL
The lattice energy of the compounds is distributed in the following decreasing order of magnitude: MgO > CaO > NaF > KCl.
<h3>KCl or NaF, which has a higher lattice energy?</h3>
The lattice energy increases with increasing charge and decreasing ion size.(Refer to Coulomb's Law.)MgF2 > MgO.Following that, we can examine NaF and KCl (both of which have 1+ and 1-charges), as well as atomic radii.NaF will have a larger LE than KCl since Na is smaller then K and F was smaller than Cl.
<h3>MgO or CaO, which has a larger lattice energy?</h3>
MGO is more difficult than CaO, hence.This is because "Mg" (two-plus) ions are smaller than "Ca" (two-plus) ions in size.MgO has higher lattice energy as a result.
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In chemical reactions, the actual yield is not the same as the expected yield . Actual yield is lower than the theoretical yield . Then we have to find the yield percentage. To see what percentage of the theoretical yield is the actual yield.
Percent yield = actual yield / theoretical yield x 100%
Percent yield = 24.6/55.9 x100%
Percent yield = 44%
The correct answer is <span>Antoine-Laurent de Lavoisier. Hope this helps!</span>