0.000132 g of hydrated sodium borate (Na₂B₄O₇ · 10 H₂O)
Explanation:
First we need to find the number of moles of sodium borate (Na₂B₄O₇) in the solution:
molar concentration = number of moles / volume (L)
number of moles = molar concentration × volume (L)
number of moles of Na₂B₄O₇ = 0.1 × 0.5 = 0.05 moles
We know now that we need 0.05 moles of hydrated sodium borate (Na₂B₄O₇ · 10 H₂O) to make the solution.
Now to find the mass of hydrated sodium borate we use the following formula:
number of moles = mass / molar weight
mass = number of moles × molar weight
mass of hydrated sodium borate = 0.05 / 381 = 0.000132 g
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molar concentration
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Answer:
2.3
Explanation:
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Answer:
1033.36g
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This means that 1 mole of SO2 also contains 6.02x10^23 molecules.
1 mole SO2 = 32 + (16x2) = 64g.
Now, If 64g of SO2 contains 6.02x10^23 molecules,
Therefore, Xg of SO2 will contain 9.72x10^24 i.e
Xg of SO2 = (64x9.72x10^24)/6.02x10^23
Xg of SO3 = 1033.36g.
Therefore, 1033.36g of SO2 contains 9.72x10^24 molecules
Answer:- C. The container contains 8 grams of liquid water and no ice.
Explanations:- In thermodynamics, "An open system is the one that exchanges energy and matter with it's surroundings."
If we look at all the choices then the total mass is 12 grams except for choice C. So, the correct choice is C as the mass in the container remains 8 grams since some of the amount is lost to the surroundings in the form of water vapors.
