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3 years ago

What are the differences between boiling and evaporation

Chemistry

1 answer:

Gnesinka [82]3 years ago

7 0

Answer/Explanation:

Let's define both terms

Boiling: is defined as a process whereby the liquid state is turned into gaseous state at a specific boiling point. And it is a fast process.

Evaporation: is defined as a process whereby a natural process in which the increase in temperature or pressure causes liquid to change into gas.

Difference between boiling and evaporation

In boiling, temperature of the liquid remains constant. While in evaporation, temperature of the liquid reduces

In boiling, temperature is required only at boiling point while in evaporation, temperature occurs at any given temperature.

In boiling, bubbles are formed while in evaporation, bubbles are not formed.

In boiling, a source of energy is required while in evaporation, the surrounding supplies the energy required.

Boiling produces heat and does not lead to liquid cooling, evaporation leads to liquid cooling.

The molecules of the liquid move faster in boiling than in evaporation

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Sulfuric acid (H₂SO₄), is formed when sulfur dioxide (SO₂) reacts with oxygen and water. Using the balanced chemical reaction ab

Lynna [10]

Answer:

8.5 mol H₂SO₄

Explanation:

It seems the balanced reaction the problem is referring to is absent, however the description matches the following balanced reaction:

2SO₂ + O₂ + 2H₂O → 2H₂SO₄

Now we <u>can convert 8.5 moles of SO₂ into moles of H₂SO₄</u>, using <em>the stoichiometric coefficients of the balanced reaction</em>:

8.5 mol SO₂ * $\frac{2molH_2SO_4}{2molSO_2}$ = 8.5 mol H₂SO₄

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3 years ago

Acetylene is hyrodgenated to form ethane. The feed to the reactor contains 1.60 mol H2/mol C2H2. The reaction proceeds to comple

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Answer:

Explanation:

C₂H₂ + 2H₂ = C₂H₆

1 mole 2 mole 1 mole

Feed of reactant is 1.6 mole H₂ / mole C₂H₂

or 1.6 mole of H₂ for 1 mole of C₂H₂

required ratio as per chemical reaction written above

2 mole of H₂ for 1 mole of C₂H₂

So H₂ is in short supply . Hence it is limiting reagent .

1.6 mole of H₂ will react with half of 1.6 mole or .8 mole of C₂H₂ to form .8 mole of C₂H₆

a )Calculate the stoichiometric reactant ratio = mole H₂ reacted/mole C₂H₂ reacted

= 1.6 / .8 = 2 .

b )

yield ratio = mole C₂H₆ formed / mole H₂ reacted ) = 0.8 / 1.6 = 1/2 = 0.5 .

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3 years ago

g A laboratory analysis of an unknown compound found the following composition: C 75.68% ; H 8.80% ; O 15.52%. What is the empir

sammy [17]

Answer:

THE EMPIRICAL FORMULA FOR THE UNKNOWN COMPOUND IS C7H9O

Explanation:

The empirical formula for the unknown compound can be obtained by following the processes below:

1 . Write out the percentage composition of the individual elements in the compound

C = 75.68 %

H = 8.80 %

O = 15.52 %

2. Divide the percentage composition by the atomic masses of the elements

C = 75 .68 / 12 = 6.3066

H = 8.80 / 1 = 8.8000

O = 15.52 / 16 = 0.9700

3. Divide the individual results by the lowest values

C = 6.3066 / 0.9700 = 6.5016

H = 8.8000 / 0.9700 = 9.0722

O = 0.9700 / 0.9700 = 1

4. Round up the values to the whole number

C = 7

H = 9

O = 1

5 Write out the empirical formula for the compound

C7H90

In conclusion, the empirical formula for the unknown compound is therefore C7H9O

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3 years ago

1. If a solution containing 48.99 g of mercury(II) perchlorate is allowed to react completely with a solution containing 8.564 g

Vitek1552 [10]

1. Chemical eqn:

Hg(ClO4)2 + Na2S -> HgS + 2NaClO4

mercury perchlorate has a molar mass of 399.5g/mol (1d.p) and for Na2S it is 78.0g/mol (1d.p.)

no. of moles of mercury perchlorate= 48.99÷399.5= 0.12263mol(5s.f.)

no. of moles of Na2S= 8.564÷78.0= 0.10979mol ( 5s.f.)

so no. of moles of Hg(ClO4)2/ no. of moles of Na2S= 1/1 according to the eqn

so no. of moles of Hg(ClO4)2 needed if all Na2S is used up is 1/1×0.10979= 0.10979 mols

since no. of moles of mercury perchlorate needed < no. of moles of it provided, it is in excess and Na2S is the limiting factor.

since HgS is a solid and NaClO4 is aqueous, solid ppt formed will only be HgS.

no. of moles of HgS/ no. of moles of NaClO4= 1/1

no. of moles of HgS produced= 0.10979mols

molar mass of HgS= 232.7g/mol 1d.p.

grams of solid produced= 232.7×0.10979= 25.5g (3s.f.)

2. reactant in excess is Hg(ClO4)2,

no. of excess moles= 0.12263-0.10979= 0.01284mols

grams of excess reactant= 0.01284×399.5= 5.13g (3s.f.)

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4 years ago

It takes 412. KJ/mol to break a carbon-hydrogen single bond. Calculate the maximum wavelength of light for which a carbon-hydrog

olga_2 [115]

Answer:

The maximum wavelength of light for which a carbon-hydrogen single bond could be broken by absorbing a single photon = 290 nm

Explanation:

So to break a single C - H bond require = $\frac{412}{6.023 X (10)^{23} }$

= 6.84 x 10⁻¹⁹ joule

Find the wavelength of a photon we use E = hν

⇒ E = $\frac{hc}{Wavelength}$

Where h = Planck's constant = 6.626 x 10⁻³⁴ J.K⁻¹.Mole⁻¹

c = speed of light = 3 x 10⁸ m/sec

Wavelength = $\frac{6.626 X 10^{-34} X 3 X 10^{8} }{6.84 X10^{-19} }$

= 2.9 x 10⁻⁷ m

= 290 nm

∵ 1 nm = 10⁻⁹ m

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4 years ago