Answer:
A larger image is produced when
> ![d_o](https://tex.z-dn.net/?f=d_o)
A smaller image is produced when
< ![d_o](https://tex.z-dn.net/?f=d_o)
An upright image is produced when m is positive
An upright image is produced when m is negative
Explanation:
The mirror equation is given as follows;
![\dfrac{1}{f} = \dfrac{1}{d_i} + \dfrac{1}{d_o}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%20%3D%20%5Cdfrac%7B1%7D%7Bd_i%7D%20%2B%20%5Cdfrac%7B1%7D%7Bd_o%7D)
![m =-\dfrac{d_i}{d_o} = \dfrac{h_i}{h_o}](https://tex.z-dn.net/?f=m%20%3D-%5Cdfrac%7Bd_i%7D%7Bd_o%7D%20%3D%20%5Cdfrac%7Bh_i%7D%7Bh_o%7D)
For concave mirrors, f = focal length
= Image distance from the mirror (-ve
= Image is behind the mirror +ve
= Image is in front of the mirror)
= Object distance from the mirror (-ve
= Object is behind the mirror +ve
= Object is in front of the mirror)
m = Magnification (-ve m = Inverted image +ve m = upright image)
= Image height
= Object height
f = Focal length of the mirror
To produce a larger image
> ![d_o](https://tex.z-dn.net/?f=d_o)
To produce a smaller image
< ![d_o](https://tex.z-dn.net/?f=d_o)
To produce an upright image, m should be positive hence,
will be negative or the image will appear behind the mirror
To produce an inverted image, m should be negative hence,
will be positive or the image will form in front of the mirror.