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Vinvika [58]
3 years ago
8

A diver with a mass of 80.0 kg jumps from a dock into a 130.0 kg boat at rest on the west side of the dock. if the velocity of t

he diver in the air is 4.10 m/s to the west, what is the final velocity of the diver after landing in the boat?
Physics
1 answer:
Bogdan [553]3 years ago
8 0
Applying conservation of momentum;

m_{1}  v_{1} + m_{2}  v_{2} = m_{f}  v_{f}

Where m1 = 80.0 kg; v1 =4.10 m/s; m2 = 130.0 kg; v2 = 0; mf = (80+130) kg; vf = ??

Therefore,
80*4.1 + 130*0 = 210*vf
vf = (80*4.1)/210 = 1.56 m/s
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A person walks 20.0° north of east for 3.20 km. How far would she have to walk due north and due east to arrive at the same loca
aivan3 [116]

Answer:

1.09 km, 3 km

Explanation:

displacement, d = 3.20 km at 20° North of east

A vector quantity has two components one along the x axis and the other is along Y axis. the component along X axis is called the horizontal component and it is due east.

The component along y axis is called vertical component and it is due North.

Displacement due North, dy = 3.20 Sin 20° = 1.09 km

Displacement due east, dx = 3.20 Cos 20° = 3 km

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6 0
3 years ago
Read 2 more answers
A particle has ~r(0) = (4 m) ˆ and ~v(0) = (2 m/s)ˆı. If its acceleration is constant and given by ~a = −(2 m/s 2 ) (ˆı +ˆ), a
Troyanec [42]

The particle has \vec r(0)=(4\,\mathrm m)\,\vec\imath and \vec v(0)=\left(2\frac{\rm m}{\rm s}\right)\,\vec\imath, and is undergoing a constant acceleration of \vec a=-\left(2\frac{\rm m}{\mathrm s^2}\right)(\vec\imath+\vec\jmath).

This means its position at time t is given by the vector function,

\vec r(t)=\vec r(0)+\vec v(0)t+\dfrac12\vec a t^2

\implies\vec r(t)=\left[4\,\mathrm m+\left(2\dfrac{\rm m}{\rm s}\right)t-\left(1\dfrac{\rm m}{\mathrm s^2}\right)t^2\right]\,\vec\imath-\left(1\dfrac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath

The particle crosses the x-axis when the \vec\imath component is 0 for some time t>0, so we solve:

4+2t-t^2=0\implies t^2-2t+1=5

\implies(t-1)^2=5

\implies t-1=\pm\sqrt5

\implies t=1\pm\sqrt5

The negative square root introduces a negative solution that we throw out, leaving us with \boxed{t=1+\sqrt5} or about 3.24 seconds after it starts moving.

3 0
4 years ago
Plz help........................
hoa [83]

Answer:

The correct wording is

  1. Pressure increases with the depth of the fluid.
  2. A plane's engines produce thrust to push the plane forward.
  3. A fluid can be a liquid or a gas.
  4. A hydraulic device uses Pascal's principle to lift or move objects.
  5. lift is the upward force exerted on objects by fluids.

Explanation:

1. As you go deeper into a fluid,<em> there is more of it on top of you; </em>therefore, the pressure excreted on you is greater.

2. A plane's engines pushes the air in opposite direction, which according to newton's third law, produces necessary force to move the plane forward.

3.  <em>A fluid has no fixed shape,</em> and it deforms under the influence of external forces applied—liquid and gases fit into this definition.

4. Pascal's principle <em>says that pressure applied on one region of the fluid must equal pressure transmitted to another region of the same fluid</em>. This principle is used in a hydraulic device to exert forces on fluids to lift objects that would otherwise be difficult to move.

5. By definition, the upward force exerted by the fluids on objects is the lift.

7 0
3 years ago
a measuring cylinder contains 30cm3 of a liquid some more of the liquid is added until the liquid level reaches the 50cm3 mark t
S_A_V [24]

Answer:

1.5g/cm³

Explanation:

Given parameters:

Initial volume of the liquid  = 30cm³

Final volume of the liquid  = 50cm³

Mass of the liquid  = 30g

Unknown:

Density of the liquid  = ?

Solution:

Density is the mass per unit volume of a substance.

  Density  = \frac{mass}{volume}  

volume of the liquid  = final volume - initial volume  =  50cm³  -  30cm³

 volume of the liquid  = 20cm³

Density  = \frac{30}{20}   = 1.5g/cm³

6 0
3 years ago
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