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Vinvika [58]
3 years ago
8

A diver with a mass of 80.0 kg jumps from a dock into a 130.0 kg boat at rest on the west side of the dock. if the velocity of t

he diver in the air is 4.10 m/s to the west, what is the final velocity of the diver after landing in the boat?
Physics
1 answer:
Bogdan [553]3 years ago
8 0
Applying conservation of momentum;

m_{1}  v_{1} + m_{2}  v_{2} = m_{f}  v_{f}

Where m1 = 80.0 kg; v1 =4.10 m/s; m2 = 130.0 kg; v2 = 0; mf = (80+130) kg; vf = ??

Therefore,
80*4.1 + 130*0 = 210*vf
vf = (80*4.1)/210 = 1.56 m/s
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Answer:

a) F = 2250 Ib

b) F = 550 Ib

c) new max force ( F newmax ) = 2850 Ib

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