C. No Association
This is because there is no definitive line in the graph or upwards or downwards trend
The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
0234576 You just need to put the numbers in order form least to greatest and leave an even number at the end.
The mean, the median and the mode are measures of central tendency, and they are related in some many ways, depending on the type of distribution.
The median of the moderately asymmetrical distribution is 26
The given parameters are:


For a moderately asymmetrical distribution, the mean, median and mode are related by the following equation:

Substitute known values


Collect like terms


Divide both sides by 3

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