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ElenaW [278]
3 years ago
5

For which value of x is the equation 3(3 + x) = 15 + x true?

Mathematics
2 answers:
seraphim [82]3 years ago
7 0

<u>Answer:</u>

x=3

<u>Step-by-step explanation:</u>

3(3 + x)=15+x

<u>distribute</u>

9 + 3x=  15+x

<u>subtract x from each side</u>

9+3x-x = 15

9+2x = 15

<u>subtract 9 from each side</u>

9+2x-9 = 15-9

2x = 6

<u>divide by 2</u>

2x/2 = 6/2

x=3

Ymorist [56]3 years ago
7 0

Answer:

X = 3

Step-by-step explanation:

To solve for x, you can first divide both sides of the equation by 3. The reason you do this is because the left side is being multiplied by 3, so dividing would cancel it out

(3(3 + x) = 15 + x)/3   =  3 + x = 5 + 1/3x

Now, subtract 3 from both sides to isolate x on the left side

x = 2 + 1/3x

Lastly, subtract 1/3x from both sides

2/3x = 2

Now, divide both sides by 2/3 to get x = 3.

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Use pi=3<br> Calculate the area of a circle with a diameter of 10cm
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PLEASE HELP WITH 1-3 ILL MARK U THE BRAINLIEST
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Answer:

1:A(-6,-1) B(-14,0) C(-11,4)

2:D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3:H(-4,1) I(-4, 6) J(0,6) K(0,1)

Step-by-step explanation:

Before we begin, lets define the transformations:

(x, y)

T(a, b) = (x+a, y +b)

Rxaxis = (x, -y)

Ryaxis = (-x, y)

r(180, 0) = (-x, -y)

D.5(1/2x, 1/2y)

R(-90, O) = (-y, x)

1. T. A(6,-1) B(14,0) C(11,4)

   Rx. A(6, 1) B(14,0) C(11,-4)

   r180 A(-6,-1) B(-14,0) C(-11,4)

2. Rx D(-12,-6) E(-4,-6) F(-6, -9) G(-10, -9)

   Ry D(12,-6) E(4,-6) F(6, -9) G(10, -9)

   D.5 D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3. Rx=1 H(-1,2) I(4, 2) J(4,-2) K(-1,-2)

   T H(1,4) I(6, 4) J(6,0) K(1,0)

   r-90 H(-4,1) I(-4, 6) J(0,6) K(0,1)

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3 years ago
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