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Brut [27]
3 years ago
5

What do you mean by population size explain​

Physics
1 answer:
torisob [31]3 years ago
8 0
Population size is the actual number of individuals in a population. Population density is a measurement of population size per unit area, i.e., population size divided by total land area. Abundance refers to the relative representation of a species in a particular ecosystem.
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A industrial (large) pressure cooker operates at 275 kPa. Initially there is 10 kg of water at 20°C, the cooker is operated unt
alex41 [277]

Answer:

Q_{in} = 25349.92\,kJ

Explanation:

Let establish a control volume in the industrial pressure cooker, which is a transient state system. From the First Law of Thermodynamics, the heating process is modelled:

Q_{in} + m_{1}\cdot h_{1} - m_{2}\cdot h_{2} = (m_{1}-m_{2})\cdot u_{2} - m_{1}\cdot u_{1}

The heat transfered to the cooker is:

Q_{in} = m_{2}\cdot h_{2} - m_{1}\cdot h_{1} + (m_{1}-m_{2})\cdot u_{2}-m_{1}\cdot u_{1}

Properties at each state are described below:

State 1

u_{1} = 83.913\,\frac{kJ}{kg}

h_{1} = 83.915\,\frac{kJ}{kg}

State 2

u_{2} = 2540.1\,\frac{kJ}{kg}

h_{2} = 2720.9\,\frac{kJ}{kg}

The heat transfered to the cooker is:

Q_{in} = (9\,kg)\cdot (2720.9\,\frac{kJ}{kg} ) - (10\,kg)\cdot (83.915\,\frac{kJ}{kg} ) + (1\,kg) \cdot (2540.1\,\frac{kJ}{kg} )-(10\,kg)\cdot (83.913\,\frac{kJ}{kg} )

Q_{in} = 25349.92\,kJ

7 0
3 years ago
A playground merry-go-round of radius R = 1.20 m has a moment of inertia I = 240 kg · m2 and is rotating at 9.0 rev/min about a
Vesnalui [34]

Answer:

ω' = 0.815 rad/s

Explanation:

Given,

R = 1.20 m

Inertia of merry-go- round= 240 kg.m²

Rotating speed  = 9 rpm = 9\times \dfrac{2\pi}{60}

                           =0.9424 rad/s

mass of the child, m = 26 kg

angular speed of the merry-go-round=?

we know

Angular momentum, L = I ω

Moment of inertia of the child

I' = m  r² = 26 x 1.2² = 37.44 kgm²

Conservation of angular momentum

initial angular momentum = Final angular momentum

I ω = (I+I')ω'

240 x 0.9424 = (240+37.44) ω'

226.176= 277.44 ω'

ω' = 0.815 rad/s

new angular speed of the merry-go- round is equal to 0.815 rad/s

3 0
4 years ago
What is the mass of a sample whose specific heat is 6.28 J/g·°C if the sample absorbs 19.4 J and has a temperature increase of 2
kolbaska11 [484]
We have: Q = m.s.Δt
m = Q / s.Δt
Here, Q = 19.4 J
s = 6.28 J/g C
Δt = 22.9

Substitute their values into the expression:
m = 19.4 / 6.28×22.9
m = 19.4 / 143.81
m = 0.135 g

In short, Your Answer would be Option A

Hope this helps!
8 0
4 years ago
Physcs Questions from 8th grade....
scoray [572]

1).  Yes.  An object can be moving if the net force acting on the object is zero. 
A non-zero net force is required to CHANGE the object's motion ... speed it up,
slow it down, or change its direction.  But no force is required to keep it moving
at a constant speed in a straight line.

2).a).  The motion of the box changes, from not moving to moving. 
So the forces acting on it must be unbalanced.

2).b).  The motion of the box doesn't change.  It goes from not moving
to still not moving.  So the forces acting on it must be balanced.

2).c).  The motion of the box changes.  Its speed decreases. 
So the forces acting on it must be unbalanced.


4 0
3 years ago
Find the uncertainty in position (in nm) associated with an electron that is moving with a velocity of 572 km/s. The uncertainty
Salsk061 [2.6K]

Answer:

c

Explanation:

7 0
3 years ago
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