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ollegr [7]
3 years ago
6

Short-wavelength radiation from the Sun passes through a planet's atmosphere but some of the outgoing long-wavelength energy is

absorbed and radiated again; this process is known as_________.
Physics
1 answer:
serious [3.7K]3 years ago
8 0

Answer:Greenhouse effect

Explanation:

Short wavelength radiation from the sun passes through a  planet's atmosphere but some of the outgoing long-wavelength energy is absorbed and radiated again this process is known as Green house effect which increases the temperature of earth and as a result causes more to be trapped inside earth atmosphere.      

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A plane leaves the airport in Galisteo and flies 160 km at 66.0 ∘ east of north; then it changes direction to fly 260 km at 49.0
user100 [1]

<u>The question doesn't have any particular requirement, but we'll compute the displacement of the plane from its initial and final landing point in the pasture </u>

Answer:

\displaystyle |\vec{r}|=321.464\ km

\displaystyle \theta =-19.395^o

Explanation:

<u>Displacement </u>

The vector displacement \vec r is a measure of the change of position of a moving object. The displacement doesn't depend on the path followed, only on the final and initial positions. Its scalar counterpart, the distance, does measure the total space traveled and considers all the changes in the direction taken by the object. To find the displacement, we must add all the particular displacements by using vectors.

The plane first flies 160 km at 66° east of north. To find the vector expression of this displacement, we must know the angle with respect to the East direction or North of East. Knowing the angle East of North is 66°, the required angle is 90°-66°=34°

The first vector is expressed as

\displaystyle \vec{r_1}=\left \langle 160^o\ cos34^o, 160\ sin34^o \right \rangle

\displaystyle \vec{r_1}=\left \langle 132.646, 89.471 \right \rangle

The second displacement is 260 km at 49° South of East. This angle is below the horizontal respect to the reference, thus we use -49°.  

The second vector is expressed as:

\displaystyle \vec{r_2}=\left \langle 260\ cos(-49^o), 260\ sin(-49^o)\right \rangle

\displaystyle \vec{r_2}=\left \langle 170.575,-196.224\right \rangle

The total displacement is computed as the vectorial sum of both vectors

\displaystyle \vec{r}=\vec{r_1}+\vec{r_2}=\left \langle 132.646+170.575\right \rangle+ \left \langle89.471-196.224\right \rangle

\displaystyle \vec{r}=\left \langle 303.221,-106.753\right \rangle\ km

The magnitude of the total displacement is

\displaystyle |\vec{r}|=\sqrt{303.221^2+(-106,753)^2}

\displaystyle |\vec{r}|=321.464\ km

And the direction is

\displaystyle tan\ \theta =\frac{-106.753}{303.221}=-0.352

\displaystyle \theta =-19.395^o

6 0
3 years ago
The inner and outer surfaces of a 5m x 6m brick wall of thickness 30 cm and thermal conductivity 0.69 w/m.0 c are maintained at
Volgvan
The working equation to be used here is written below:

Q = kA(T₁ - T₂)/Δx
where
Q is the rate of heat transfer
k is the heat transfer coefficient
A is the cross-sectional area of the wall
T₁ - T₂ is the temperature difference between the sides of the wall
Δx is the thickness of the wall

The solution is as follows:

Q = (0.69 W/m²·°C)(5 m × 6 m)(50°C - 20°C)/(30 cm * 1 m/100 cm)
Q = 2,070 W/m

4 0
3 years ago
1. ____ outer planet 2. ____ density
mestny [16]

\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}

1. Outer planets - c. gaseous, spherical, cleared its neighborhood.

2. Density - f. amount of matter in an object, in a given space.

3. Orbital distance - e. Distance between any planet and the sun.

4. Mass - a. Amount of matter in an object.

5. Asteroid - b. Irregular rock orbiting between mars and Jupiter.

6. Volume - d. amount of space an object takes up.

  • Thanks
  • Hope it helps
6 0
3 years ago
Read 2 more answers
Two violinists are trying to play in tune. However, whenever they play their A string at the same time they hear a beat frequenc
kaheart [24]

Answer:

The possible frequencies for the A string of the other violinist is 457 Hz and 467 Hz.

(3) and (4) is correct option.

Explanation:

Given that,

Beat frequency f = 5.0 Hz

Frequency f'= 462 Hz

We need to calculate the possible frequencies for the A string of the other violinist

Using formula of frequency

f'=f_{1}-f...(I)

f'=f_{1}+f...(II)

Where, f= beat frequency

f₁ = frequency

Put the value in both equations

f'=462-5=457\ Hz

f'=462+5=467\ Hz

Hence, The possible frequencies for the A string of the other violinist is 467 Hz and 457 Hz.

4 0
3 years ago
Suppose that 4 charged particles, all having a positive charge Q, are placed and fixed at the vertices of a square, where every
algol [13]

Answer:

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3 years ago
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