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Snowcat [4.5K]
3 years ago
15

Is it exponential, linear, or quadratic? What is the equation?

Mathematics
1 answer:
bija089 [108]3 years ago
3 0

Answer:

the first is a linear

second is an exponential

third is quadratic

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If my current grade is a 65.50 percent and I get an 98 percent on a 60 point test what will be my new percentage
ioda

Answer:

81.75%

Step-by-step explanation:

98 percent on a 60 point test is 59/60

65.50+98/2 = 81.75%

8 0
2 years ago
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Please help solve this!
In-s [12.5K]

By dropping a perpendicular from the top of the isosceles triangle to the base and using the Pythagorean Theorem we quickly determine that the height of the triangle is 4.

Therefore the area of the isosceles triangle is

6•4/2=12

However, we can split the isosceles triangle into three separate triangles indicated by the red lines in the diagram below. Because the radius always meets a tangent at a right angle the area of each triangle will be the length of the side multiplied by the radius of the circle. So the total area of the isosceles triangle is given by

6r/2+2•5r/2=8r=12
8r=12
r=12/8
r=3/2

3 0
3 years ago
Assume that y varies directly with x. If y = 16 when x = 8, find y when x = 5.
dem82 [27]

Answer:

Step-by-step explanation:

5y + x = 25

Subtract x from both sides when x = 5

5y + x - x = 25 - x

5y = 20

5y/5 = 20/5

=4

Y=4

6 0
3 years ago
Solve the problem below by finding a common denominator.<br><br> 23+12
zavuch27 [327]

Answer:

35

Step-by-step explanation:

23 + 12 = 35

= (20 + 10) + (3 + 2)

= 35

7 0
3 years ago
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Find:
emmasim [6.3K]

Answer:

Step-by-step explanation:

Given the dataset 147, 154, 156, 161, 162,

Mean is the sum of the dataset divided by the total number of dataset.

a) Mean = \sum Xi/N

\overline x = \dfrac{147+154+156+161+162}{5}\\ \\\overline x = \dfrac{780}{5}\\ \\\overline x= 156

b) The formula for calculating the deviation from the mean for each value is expressed as Xi - \overline X where;

Xi is value of each item

xbar is the mean = 156

Mean deviation of 147 = 147-156 = -9

Mean deviation of 154 = 154-156 = -2

Mean deviation of 156 = 156-156 = 0

Mean deviation of 161 = 161-156 = 5

Mean deviation of 162 = 162-156 = 6

c) Sum of the deviations \sum Xi - \overline X = (-9-2+0+5+6)

\sum Xi - \overline X = -11+11

\sum Xi - \overline X = 0

<em>Hence the sum of deviation from the mean is 0</em>

5 0
3 years ago
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