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3 years ago

If the speed of an object does NOT change, the object is traveling at a

Physics

1 answer:

Elanso [62]3 years ago

5 0

Answer:

If the speed does not change at all, the object would be moving at a <u>constant speed</u>.

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The student makes a single pile of the 500 sheets of paper. Which a metre rule, she measured the height of the pile. The height

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3 years ago

a car travels 10 miles east in 30 minutes. what is its velocity in miles per hour. what is its velocity in miles per hour?

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3 years ago

Which occupies mrs space, 3m cubed or 100ft cubed

Slav-nsk [51]

The question is somewhat ambiguous.

-- It's hard to tell whether it's asking about '3 cubic meters'
or (3m)³ which is actually 27 cubic meters.

-- It's hard to tell whether it's asking about '100 cubic feet'
or (100 ft)³ which is actually 1 million cubic feet.

I'm going to make an assumption, and then proceed to
answer the question that I have invented.
I'm going to assume that the question is referring to
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I've decided to convert the meters into feet.

For 1 meter, I always use 3.28084 feet.

Then (1 meter)³ = 1 cubic meter = (3.28084 ft)³ = 35.31 cubic feet.

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3 years ago

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3 years ago

A train, traveling at a constant speed of 22.0 m/s, comes to an incline with a constant slope. While going up the incline, the t

Charra [1.4K]

Answer:

123.30 m

Explanation:

Given

Speed, u = 22 m/s

acceleration, a = 1.40 m/s²

time, t = 7.30 s

From equation of motion,

v = u + at

where,

v is the final velocity

u is the initial velocity

a is the acceleration

t is time

V = at + U

using equation v - u = at to get line equation for the graph of the motion of the train on the incline plane

$V_{x} = mt + V_{o}$ where m is the slope

Comparing equation (1) and (2)

$V = V_{x}$

a = m

$U = V_{o}$

Since the train slows down with a constant acceleration of magnitude 1.40 m/s² when going up the incline plane. This implies the train is decelerating. Therefore, the train is experiencing negative acceleration.

a = - 1.40 m/s²

Sunstituting a = - 1.40 m/s² and u = 22 m/s

$V_{x} = -1.40t + 22$