The force needed to accelerate an elevator upward at a rate of
is 2000 N or 2 kN.
<u>Explanation:
</u>
As per Newton's second law of motion, an object's acceleration is directly proportional to the external unbalanced force acting on it and inversely proportional to the mass of the object.
As the object given here is an elevator with mass 1000 kg and the acceleration is given as
, the force needed to accelerate it can be obtained by taking the product of mass and acceleration.
![\text {Force}=\text {Mass} \times \text {Acceleration}](https://tex.z-dn.net/?f=%5Ctext%20%7BForce%7D%3D%5Ctext%20%7BMass%7D%20%5Ctimes%20%5Ctext%20%7BAcceleration%7D)
![\text { Force }=1000 \times 2=2000 \mathrm{N}=2 \text { kilo Newon }](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Force%20%7D%3D1000%20%5Ctimes%202%3D2000%20%5Cmathrm%7BN%7D%3D2%20%5Ctext%20%7B%20kilo%20Newon%20%7D)
So 2000 N or 2 kN amount of force is needed to accelerate the elevator upward at a rate of
.
Answer: D. 0.57
Explanation:
The formula to calculate the eccentricity
of an ellipse is (assuming the moon's orbit in the shape of an ellipse):
![e=\frac{r_{a}-r_{p}}{r_{a}+r_{p}}](https://tex.z-dn.net/?f=e%3D%5Cfrac%7Br_%7Ba%7D-r_%7Bp%7D%7D%7Br_%7Ba%7D%2Br_%7Bp%7D%7D)
Where:
is the apoapsis (the longest distance between the moon and its planet)
is the periapsis (the shortest distance between the moon and its planet)
Then:
![e=\frac{r_{a}-0.27 r_{a}}{r_{a}+0.27 r_{a}}](https://tex.z-dn.net/?f=e%3D%5Cfrac%7Br_%7Ba%7D-0.27%20r_%7Ba%7D%7D%7Br_%7Ba%7D%2B0.27%20r_%7Ba%7D%7D)
![e=\frac{0.73 r_{a}}{1.27 r_{a}}](https://tex.z-dn.net/?f=e%3D%5Cfrac%7B0.73%20r_%7Ba%7D%7D%7B1.27%20r_%7Ba%7D%7D)
This is the moon's orbital eccentricity
it would be C laminated soda lime glass