Answer:
250N
Explanation:
According to newton second law,
\sumF = ma
Fm - Ff = ma
Since the velocity is constant, a = 0m/s
Frictional force Ff = 250N
Substitute
Fm - 250 = m(0)
Fm - 250 = 0
Fm = 250N
Hence the force to keep the box sliding at constant speed is 250N
Answer:
F = 780 [N]
Explanation:
To solve this problem we must use newton's second law which tells us that the sum of forces on a body must be equal to the product of mass by acceleration
ΣF =m*a
where:
F = force [N] (units of Newtons)
m = mass = 2600 [kg]
a = acceleration = 0.3 [m/s²]
F = 2600*0.3
F = 780 [N]
Answer:
-3.63 degree Celsius
Explanation:
We are given that
Boiling point of solution=
C
Boiling point water=100 degree Celsius
Where 
=Boiling point of solution
Boiling point of pure solvent
C
Using the formula
Molality,
m
Using the formula
We know that
Where 
=Freezing point of solvent
Freezing point of solution
Using the formula
Freezing point of water=0 degree Celsius
Hence, the freezing point of solution=-3.63 degree Celsius
Answer:
2.5 m/s^2
Explanation:
the formula for acceleration (or the one you use in this case) is a=vf-vi/t
where vf is equal to final velocity, vi is equal to initial velocity, and t is equal to time.
vf= 25 m/s
vi= 0m/s
t=10s 25-0=25, 25/10=2.5 therefore it is 2.5m/s^2
