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slega [8]
3 years ago
11

I + I -----> I2 + 146.3 kJ Is this reaction exothermic or endothermic?

Chemistry
1 answer:
elixir [45]3 years ago
6 0
This reaction is endothermic!
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What are the balanced chemical equations for Hydrochloric acid and potassium hydroxide?
-Dominant- [34]
HCl(aq) + KOH(s) --> KCl(aq) + H2O(l)
7 0
3 years ago
PLEASE HELP ME WITH THIS I WILL GIVE YOU POINTS
eduard

Answer:

1. a

2. c

3. b

4. f

5. d

6. e

Explanation:

7 0
3 years ago
How many moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 100.0 kPa and a temperature of 100.0 degrees Cel
o-na [289]

1.137448506 mol moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 100.0 kPa and a temperature of 100.0 degrees Celsius.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas. The terms are: p = pressure, in pascals (Pa). V = volume, in m^3.

We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol:

PV= nRT

Given data:

P=100.0 kPa =0.986923 atm

T=100 degree celcius= 100 + 273 =373 K

V=35.5 L

Substituting the values in the equation.

n= \frac{\;0,98 \;atm \;X \;35,5 \;L }{\;0,082\;atm / \;K mol \;X \;373 K}

n= 1.137448506 mol

Hence, 1.137448506 mol moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 100.0 kPa and a temperature of 100.0 degrees Celsius.

Learn more about ideal gas here:

brainly.com/question/16552394

#SPJ1

7 0
2 years ago
I will mark brainliest!
olganol [36]

Answer:

C ! :)

Explanation:

8 0
3 years ago
Read 2 more answers
6.0L of a gas exert a pressure of 2.5 atm. When the pressure is increased to 10.0atm what is the new volume of the gas
jeka57 [31]

Answer:

<h2>1.5 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{6 \times 2.5}{10}  =  \frac{15}{10}  =  \frac{3}{2}  \\

We have the final answer as

<h3>1.5 L</h3>

Hope this helps you

7 0
3 years ago
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