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liq [111]
3 years ago
14

How many grams of Fe2+ are there in 0.003109 moles of Fe2+?

Chemistry
1 answer:
Sergio [31]3 years ago
7 0

Answer: 0.174 g

Explanation:

First of all understand that charge on an atom like here 2+ will not vary molar mass. because ions are formed by loss or gain of electrons and electrons do not contribute to the mass of an atom or ion. so losing or gaining electron doesnt create any difference.

molar mass of Fe, i.e. mass of 1 mole of Fe is 56 g. So, mass of 1 mole of Fe2+ will also be 56 g.

given is 0.003109 moles of Fe2+,

Use maths,

1 mole of Fe2+ weighs 56 g

So, 0.003109 moles will weigh = (56 g / 1 mol ) x 0.003109 = 0.174 g.

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What is the molality of a solution containing 10.0 G of NA2 S04 and 1000.0 G of water
galina1969 [7]

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we need to find the molality of a solution containing 10.0 g of dissolved in  Na₂S0₄1000.0 g of water

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Na:  2 x 22.99= 45.98

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To find the number of moles divide 10.0g by 142.05 g/mol.

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For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.

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