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givi [52]
2 years ago
7

Based on the passage, what is the structure of the product of the reaction between 8-hydroxyquinoline-5 sulfonate and hrp?.

Chemistry
1 answer:
Mashutka [201]2 years ago
4 0

A because the end result of this reaction is a radical created by the oxidation of an aromatic amine's or phenol's ring substituent. The hydroxyl group of a phenol acts as the ring substituent in this situation.

<h3>Which two enzyme types are required for the two-step process of converting cytosine to 5 hmC?</h3>
  • The methyl group is transferred to cytosine in the first stage, and it is then hydroxylated in the second step.
  • Therefore, a transferase and an oxidoreductase are the two groups of enzymes required.

<h3>Which kind of interaction between proteins and the dextran column material is most likely to take place?</h3>
  • Hydrogen bonding because the glucose's OH would form an H-bond with any exposed polar side chains on a protein surface.

<h3>Two out of the four proteins would adhere to a cation-exchange column at what buffer pH? </h3>
  • Only positively charged proteins can bind to a cation-exchange column, and this can only happen when the pH is lower than the pI.
  • Proteins A and B would both be positively charged at pH 7.0.

To learn more about hydroxyquinoline visit:

brainly.com/question/26102339

#SPJ4

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4 0
3 years ago
Recently, the United States government decided to construct a huge crypt in the middle of Yucca Mountain in Nevada to bury high-
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4 0
3 years ago
Read 2 more answers
Pls help asap!!!!
AVprozaik [17]

Answer: The pressure of the He is 2.97 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_{N_2}+p_{O_2}+p_{He}.

Given : p_{total} =total pressure of gases = 6.50 atm

p_{N_2} = partial pressure of Nitrogen = 1.23 atm

p_{O_2} = partial pressure of oxygen = 2.3 atm

p_{He} = partial pressure of Helium = ?

putting in the values we get:

6.50atm=1.23atm+2.3atm+p_{He}  

p_{He}=2.97atm

The pressure of the He is 2.97 atm

3 0
3 years ago
If 0.2 g of nitrobenzene are added to 10.9 g of naphthalene, calculate the molality of the solution. (given: molar mass of nitro
In-s [12.5K]

Molality is defined as 1 mole of a solute in 1 kg of solvent.  

Molality=

\frac{Number of moles of solute}{Mass of solvent in kg}

Number of moles of solute, n=  

\frac{Given mass of the substance}{Molar mass of the substance}

Given mass of the nitrobenzene=0.2 g

Molar mass of the substance= 123.06 g mol⁻¹

Number of moles of nitrobenzene,  

n= \frac{0.2 }{123.06}

Number of moles of nitrobenzene, n= 0.0016  mol

Mass of 10.9 g of naphthalene in kg=0.0109  

Molality= \frac{0.0016}{0.0109 }

Molality= 0.146 m

7 0
3 years ago
above shows a balloon full of gas which has a volume of 120.0ml at 300.0k assuming pressure remains constant , what is the voume
trasher [3.6K]

128 ml  is the voume of the balloon if the temperature of the gas increases to 320.0k.

Explanation:

given that:

T1 (initial temperature) = 300K

V1 ( initial volume) =  120ml

T2 (final temperature) = 320 K

V2 (final volume) = ?

Pressure remained constant throughout the process.

From the equation

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Since pressure is constant the equation will be:

\frac{V1}{T1} = \frac{V2}{T2}

V2 = \frac{V1 X T2}{T1}

    Putting the values in the above formula:

V2 = \frac{120 X 320}{300}

     = 128 ml

128 ml is the volume of the gas if temperature increases from 3OO K to 320k

4 0
3 years ago
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