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makkiz [27]
3 years ago
14

Someone pls help me do this and don't ask for brainliest or say random answers not related to this.

Computers and Technology
2 answers:
Art [367]3 years ago
4 0
21 is Gradient not 9.

9 is supposed to be blur/sharpened.
Marat540 [252]3 years ago
3 0
I used to use pixlr all the time so i should know.
Ok so

1 is picker
2 is lasso select
3 is crop
4 is Liquefy
5 is clone
6 is dodge/burn
7 is Pen
8 is Eraser
9 is Gradient
10 is Text
11 is Zoom
12 is Switch Colors
13 is Marquee Select
14 is Wand select
15 is Cutout/Mask
16 is Heal
17 is Blur/Sharpen
18 is Sponge Color
19 is draw
20 is Fill
21 is I don’t know I have never seen that before
22 is Picker

So sorry if it took a while i did not know what the star was
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Answer:

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Start by guessing 2.

Compute the guess squared.

Is the guess squared close to the target number? If it’s within 0.01, we’re done. We’ll take the absolute value of the difference, in case we overshoot. (In Python, abs is the absolute value function.)

If it’s not close enough, we divide the target number by our guess, then average that value with our guess.

That’s our new guess. Square it, and go back to Step #3.

Explanation:

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Write a C++ console program to do the following: 1. Define an array of ints with the ten elements { 0, 1,2,3, 4, 5, 6, 7, 8, 9 }
Gemiola [76]

Answer:

#include<iostream>

#include <vector>

#include <list>

using namespace std;

int main(){

int a[10]={0,1,2,3, 4, 5, 6, 7, 8, 9 };

std::vector<int> v (&a[0],&a[0]+10);

std::list<int> l (&a[0],&a[0]+10);

int b[10];

for(int i=0;i<10;i++){

b[i]=a[i];

}

std::vector<int> v2(v);

std::list<int> l2(l);

for(int i=0;i<10;i++){

b[i]+=2;

}

for(int i=0;i<10;i++){

v2[i]+=3;

}

for (std::list<int>::iterator it = l2.begin(); it != l2.end(); it++)

*it=*it+5;

cout<<"Each containers value are: "<<endl;

cout<<"1st array: "<<endl;

for(int i=0;i<10;i++){

cout<<a[i]<<" ";

}

cout<<"\n 1st vector: \n";

for(int i=0;i<10;i++){

cout<<v[i]<<" ";

}

cout<<"\n 1st List is:\n";

for (std::list<int>::iterator it = l.begin(); it != l.end(); it++)

cout << *it << ' ';

cout<<"\n 2nd array: "<<endl;

for(int i=0;i<10;i++){

cout<<b[i]<<" ";

}

cout<<"\n 2nd vector:\n";

for(int i=0;i<10;i++){

cout<<v2[i]<<" ";

}

cout<<"\n 2nd list:\n";

for (std::list<int>::iterator it = l2.begin(); it != l2.end(); it++)

cout << *it << ' ';  

return 0;

}

Explanation:

  • Initialize an array, a vector and a list of type integer .
  • Create a 2nd array, vector, and list as a copy of the first array, vector, and list.
  • Increase the value of each element in the array by 2 , vector by 3 and list by 5.
  • Finally display the relevant results.
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