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dalvyx [7]
3 years ago
9

Tommy loves taking care of homing pigeons. He sent a note to his crush who lives 24.0 km away from his house. These birds fly at

a rate of 48.2 km/h. How long will the note reach Tommys crush?​
Computers and Technology
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

0.5 hours or 1800 seconds.

Explanation:

<u><em>Given the following data;</em></u>

Distance = 24km

Speed = 48.2 km/h

To find the time;

Time = distance/speed

Time = 24/48.2

Time = 0.50 hours

Converting the time to seconds;

1 hour = 3600 seconds

0.5 hour = 1800 seconds

Therefore, it would take 1800 seconds or 0.5 hours for the note to reach Tommy's crush.

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What kind of output device would not be used to output images
saveliy_v [14]

Answer:

Speakers.

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3 0
3 years ago
Write the half function. A function call and the functionprototype
EastWind [94]

Answer:

C code for half()

#include<stdio.h>

void half(float *pv);

int main()

{

float value=5.0;  //value is initialized  

printf ("Value before half: %4.1f\n", value); // Prints 5.0

half(&value);  // the function call takes the address of the variable.

printf("Value after half: %4.1f\n", value); // Prints 2.5

}

void half(float *pv) //In function definition pointer pv will hold the address of variable passed.

{

*pv=*pv/2;  //pointer value is accessed through * operator.

}

  • This method is called call-by-reference method.
  • Here when we call a function, we pass the address of the variable instead of passing the value of the variable.
  • The address of “value” is passed from the “half” function within main(), then in called “half” function we store the address in float pointer ‘pv.’ Now inside the half(),  we can manipulate the value pointed by pointer ‘pv’. That will reflect in the main().
  • Inside half() we write *pv=*pv/2, which means the value of variable pointed by ‘pv’ will be the half of its value, so after returning from half function value of variable “value” inside main will be 2.5.

Output:

Output is given as image.

3 0
3 years ago
Name the technique that uses a scheme to sum the individual digits in a number and stores the unit's digit of that sum with the
Artemon [7]

Answer:

Parity Bit

Explanation:

Given that Parity bit is a form of strategy or method that utilizes a scheme in adding a solitary bit to a binary string. This can be either 1 or 0, thereby making the total quantity of bit to become either odd parity bit or even parity bit during storage.

Hence, the technique that uses a scheme to sum the individual digits in a number and stores the unit's digit of that sum with the number is called PARITY BIT.

7 0
3 years ago
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