Question

Swer all parts. (a) What is the wavelength (in nm) of radiation that has an energy ...

Answer 1

Answer:

a) The wavelength is around 33.8 nm = 3.38*10⁻¹ nm

b) Ultraviolet

Explanation:

a) The energy (E) of a photon is related to its wavelength (λ) by the Planck's equation:

$E = h\frac{c}{\lambda}----(1)$

where h = Planck's constant = 6.626*10^-34 Js

c = speed of light = 3*10^8 m/s

E = 3.55*10^6 J/mol

The energy in terms of J/photon is:

$=\frac{3.55*10^{6} J/mol*1mol}{6.023*10^{23} photons } =5.89*10^{-18} J/photon$

Based on eq(1)

\lambda = h\frac{c}{E}=6.626*10^{-34}Js*\frac{3*10^{8}m/s}{5.89*10^{-18}J}=3.38*10^{-8}m

The wavelength is around 33.8 nm = 3.38*10⁻¹ nm

b) In the electromagnetic spectrum the ultraviolet range extends from 390 nm-8.82 nm

The calculated wavelength of 33.8 nm should fall in the UV range.