Determine the identity of the daughter nuclide from the positron emission of 6832ge. determine the identity of the daughter nucl
1 answer:
Answer:- The daughter nuclide is Gallium with atomic number 31 and mass number 68.
Explanations:- Positron emission is also known as beta plus decay. In this type of radioactive decay in which a proton changes into neutron and a positron and electron neutrino are released.
As the proton changes into neutron, mass number remains same but the atomic number decreases by one unit.
The given element is Ge with atomic number 32 and mass number 68. Mass number decreases by one unit means the atomic number of the daughter nuclide would be 31 and it is Gallium.
The equation could be written as:
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<h3>Answer:</h3>
2.04 mol CBr₄
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Organic</u>
- Writing Organic Compounds
- Writing Covalent Compounds
- Organic Prefixes
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<u>Step 1: Define</u>
675 g CBr₄
<u>Step 2: Identify Conversions</u>
Molar Mass of C - 12.01 g/mol
Molar Mass of Br - 79.90 g/mol
Molar Mass of CBr₄ - 12.01 + 4(79.90) = 331.61 g/mol
<u>Step 3: Convert</u>
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<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
2.03552 mol CBr₄ ≈ 2.04 mol CBr₄