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Gemiola [76]
3 years ago
6

For each of the following, draw the resulting wave when the two pulses occupy the same space. Unless otherwise noted, each wave

has an amplitude of +/- A.
Physics
1 answer:
frozen [14]3 years ago
4 0

Answer:

A

Explanation:

because it is are of circle

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When changing a tire sized 195/75 R15 to a 5 percent lower profile, the correct tire size would be _____
valentinak56 [21]

Answer and explanation:

When you are changing a car tire, the most important thing is to keep the total diameter as equal as possible.

The total car tire diameter can be calculated as:

D_{tot orig}=\frac{195 \cdot 75}{2540 \cdot 2}+15''=26.5''

The profile of this tire is 75 (the higher/taller relation), therefore a 5 percent lower profile would be:

pr=0.95·75=71.25

The problem is that the profiles are normalized and the nearest profile available is 70.

If we take a theorical tire with a profile of 71.25:

D_{tot orig}=D_{new}\\\frac{195 \cdot 75}{2540 \cdot 2}+15''=\frac{X \cdot 71.25}{2540 \cdot 2}+15''\\X=205.26

The theorical tire size should be 205/71 R15.

If we look for a real tire size, we should look for a tire with a diameter nearest to 26.5'' and a profile of 70.

The best option for real tire size is: Tire 225/70 R14 (wheel diameter of 26.4'') or 205/70 R15 (wheel diameter of 26.3'').

3 0
3 years ago
A JFET has a drain current of 5mA. If IDSS = 10mA and VGS ( off )= -6 v. find The Value Of
levacccp [35]

\underline {\huge \boxed{ \sf \color{skyblue}Answer :  }}

<u>Given :</u>

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{D} = 5mA

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{DSS} = 10mA

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS(off)} = -6V

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS} =   {?}

\:  \:  \:

<u>Let's Slove :</u><u> </u>

  • \tt \large  I_{D} = I_{(DSS)}  (1 -   \frac {V_{GS}}{V_{GS(off)}} )^{2}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{I_D} }{ \sqrt{I_{DSS}} } ) \times  V_{GS(off)}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{5m} }{ \sqrt{10m} } ) \times  { - 6}

\:  \:

  • \underline \color{red} {\tt \large \boxed {\tt V_{GS} = 1.75 ✓}}
3 0
1 year ago
What is the original source of hydroelectric energy
tangare [24]

Differences in land elevation result in rainfall runoff, and allow some of the original solar energy to be captured as hydro-electric power (Figure 1). Hydro power is currently the world's largest renewable source of electricity, accounting for 6% of worldwide energy supply or about 15% of the world's electricity.

hope this helps

mark brainliest  :)

6 0
3 years ago
Two parallel slits are illuminated by light composed of two wavelengths. One wavelength is λA = 622nm. The other wavelength is λ
Sergio039 [100]

Answer:

\lambda_{B}=414.67 nm

Explanation:

In this question we have given

\lambda_{A}=622nm

we have to find

\lambda_{B}=?

We know that

optical path difference for bright fringe is given as=n\lambda

Here,

n is order of fringe

and optical path difference for dark fringe is given as=(n+.5)\lambda

since the light with wavelength \lambda_{A} produces its third-order bright fringe at the same place where the light with wavelength \lambda_{B} produces its fourth dark fringe  

it means

optical path difference for 3rd order bright fringe= optical path difference for forth order dark fringe

Therefore,

3\lambda_{A}=(4+.5)\lambda_{B}...............(1)

Put value of \lambda_{A} in equation (1)

3 \times 622=(4+.5)\lambda_{B}

1866=4.5\lambda_{B}

\lambda_{B}=414.67 nm

3 0
3 years ago
Can someone love me pls
dlinn [17]

that's sad that you are trying to find love on this app :(

6 0
2 years ago
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