$\bf \textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 \\ \quad \\
a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3\\\\
-------------------------------\\\\
\boxed{64=4^3}\qquad x^3+64\implies x^3+4^3\implies (x+4)(x^2-x4+4^2)
\\\\\\
(x+4)(x^2-4x+16)$

8 0

3 years ago

Read 2 more answers

How do I do pre-Algebra???

Lana71 [14]

Hey there!

The main concept of pre-algebra is solving equations for variables in them.

For example, let's say you have the algebraic equation below.

x+1=3

With algebra, you need to figure what x is equal to. To do so, you will use inverse operations on both sides of the equation to isolate x one side, showing what it is equal to.

We would subtract 1 to both sides to isolate x on one side.

x+1-1=3-1

As you can see, +1-1=0, therefore, this would give us x+0, or just x. Now it is isolated and will show us what it is equal to.

x=3-1

x=2

Therefore, in our equation x+1=3, x would be equal to 2.

I hope this explanation helps! Have a great time here at Brainly!

7 0

3 years ago

The sum of three consecutive intergers is 267. What is the largest interger?​

The sum of three consecutive intergers is 267. What is the largest interger?