In terms of acids and bases, what does neutralization mean?.

Chemistry

1 answer:

egoroff_w [7]3 years ago

7 0

Answer:

Neutralization is when the pH (power of hydrogen ions) of a solution is at 7 (considered neutral in the pH scale). This means it's neither acidic nor basic and is neutral. In order to neutralize an acidic solution, you pour in the same amount of a strong base. And in order to neutralize a basic solution, you pour in the same amount of a strong base.

A neutralization reaction will give you salt and water. A common neutralization reaction could be:

HCl (strong acid) + NaOH (strong base) ----> NaCl (Salt) + H2O (water)

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Read 2 more answers

The formation of ammonia is represented by the equation N2(g) + 3H2(g) ⇌ 2NH3(g). Determine the enthalpy of formation of ammonia

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$\Delta _fH_{NH_3}=-66\frac{kJ}{mol}$

Explanation:

Hello!

In this case, since the study of the bond energy allows us to compute the enthalpies of some reactions, for this combination reaction by which ammonia is yielded, we understand the enthalpy of reaction equals the enthalpy of formation of ammonia, and, in terms of the bonds energy we can write:

$\Delta _fH_{NH_3}=Delta _rH=\Sigma \Delta H(bonds \ broken)-\Sigma \Delta H(bonds \ formed)$

Whereas the bonds enthalpy of those bonds that get broken cover the N≡N and the three H-H bonds at the reactants side and the enthalpy of those bonds that are formed cover the six N-H bonds at the products; which means we obtain:

$\Delta _fH_{NH_3}=942\frac{kJ}{mol} +3*436\frac{kJ}{mol}-6*386\frac{kJ}{mol}\\\\\Delta _fH_{NH_3}=-66\frac{kJ}{mol}$

Which differs from the theoretical value that is -46 kJ/mol.

Best regards!

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