The probability is 0.3, or 30%.
These are not independent events; one pill being chosen will affect the probability after that, as the pill will not be replaced before selecting the next one.
The probability of getting exactly 1 narcotic pill is given by:
(6/15)(9/14)(8/13) = 432/2730. It does not matter what order the narcotic pill is in, the overall product will be the same.
The probability of getting exactly 2 narcotic pills is given by:
(6/15)(5/14)(9/13) = 270/2730. Again, the order these are found in does not matter, as it is multiplication and will not change the product.
The probability of all 3 pills being narcotics is given by:
(6/15)(5/14)(4/13) = 120/2730.
Adding these three possibilities together, we have 822/2730 = 0.30.
Answer:
x = 18
Step-by-step explanation:
difference between y = 12, x=72 is 6
so if y = 3 then multiply 3×6 = 18
4x + 3 + x - 2 +4x +3 +x - 2
5x + 1 + 4x + 3 + x - 2
5x + 1 + 5x + 1
10x + 2
1. D none of the above.
2. A 5.43, 5.62, 5.74
3. A 75%
4. A 87.5%
5. A 0.7
6. B between 0.5 and 1.0
Answer: the correct answer is 76
Step-by-step explanation:
(APEX)
