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omeli [17]
3 years ago
10

If you good with science multiple choice

Physics
1 answer:
miss Akunina [59]3 years ago
6 0

Answer:

If it had more or less mass, the atmosphere would be very different with either too much ammonia and methane or too little oxygen and water

Explanation:

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Alec says the force of gravity is stronger on a piece of paper after it’s crumpled. His classmate, Jordan, disagrees. Alec “prov
Anika [276]
No, gravity acts equally on all objects.  The crumpled paper falls faster because it resists the drag force due to the atmosphere because of its compact size.  A flat piece of paper has an extended body and "catches" the air and falls more slowly.  In a vacuum they would fall at the same rate either way.
8 0
3 years ago
PLZ HELP I WILL GIVE BRAINLIEST
Vaselesa [24]

Answer:

12.7m/s

Explanation:

Given parameters:

Mass of diver  = 77kg

Height of jump  = 8.18m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we apply the motion equation below:

             v²   = u²  + 2gH

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

H is the height

 Now insert the parameters and solve;

       v² = 0²  +  2 x 9.8 x 8.18

     v  = 12.7m/s

8 0
2 years ago
A sound source is moving at 80 m/s toward a stationary listener that is standing in still air (a) Find the wavelength of the sou
Setler [38]

Answer:

a. wavelength of the sound, \vartheta = 1.315\vartheta_{o}

b. observed frequecy, \lambda = 0.7604\lambda_{o}

Given:

speed of sound source, v_{s} = 80 m/s

speed of sound in air or vacuum, v_{a} = 343 m/s

speed of sound observed, v_{o} = 0 m/s

Solution:

From the relation:

v = \vartheta \lambda        (1)

where

v = velocity of sound

\vartheta = observed frequency of sound

\lambda = wavelength

(a) The wavelength of the sound between source and the listener is given by:

\lambda = \frac{v_{a}}{\vartheta }         (2)

(b) The observed frequency is given by:

\vartheta = \frac{v_{a}}{v_{a} - v_{s}}\vartheta_{o}

\vartheta = \frac{334}{334 - 80}\vartheta_{o}

\vartheta = 1.315\vartheta_{o}                (3)

Using eqn (2) and (3):

\lambda = \frac{334}{1.315} = \frac{1}{1.315}\frac{v_{a}}{\vartheta_{o}}

\lambda = 0.7604\lambda_{o}

4 0
3 years ago
A 1200 kg elevator accelerated upwards at 2 m/s2. Draw a force diagram for the elevator. Calculate the force of tension in the c
pishuonlain [190]

Answer:

4800

Explanation:

You have to multiply the 1200 kg and the 2 m/s2. Then multiply the other 2 by the 2400 because it was the answer to the first part now after you multiply your answer is 4800.

6 0
3 years ago
What is 6.02 x 10^4 in standard notation
Vesnalui [34]
I believe you mean 6.02*10^7 but you want to shift the decimal 7 times to the right which would be 60200000 (:
4 0
3 years ago
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