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Dmitry_Shevchenko [17]
4 years ago
5

Commercials for a toy bouncy ball advertise that it will bounce to a height that is greater than the

Physics
1 answer:
storchak [24]4 years ago
7 0

Answer:

because energy will be lost due to friction, sound, and heat (arguably similar to friction) and ENERGY MUST STAY THE SAME so it is IMPOSSIBLE for the ball to bounce higher than when dropped!

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An elevator moves from rest<br> to 2 m/s over 8 seconds. What<br> is the elevator's acceleration?
riadik2000 [5.3K]

Answer:

0.25m/s^2

Explanation:

Acceleration= Change in velocity / time

= 2 - 0 / 8

= 2 /8

= 0.25

7 0
3 years ago
A wild ride a car in a roller coaster moves along a track that consists of a sequence of ups and downs. let the x axis be parall
Inessa05 [86]

solution:

write the coordinates of the points A and B  

A= (0,0,14)ft

B= (5,-6,0)ft

write the position vector of a with recpect to b

R_{BA}=(0-5)i+(0-(-6))j+(14-0)k

     =-5i+6k+14k

calculation of a magnitude of the vector R_{BA}

\left | R_{BA} \right |=\sqrt{(-5)^2+6^2+14^2}

                      =\sqrt{25+36+196}

                      =16.031ft

calculation of the unit vector  

\frac{-5i+6k+14k}{16.031}

calculation of the force

F_{BA}=R_{BA}U_{BA}  

here, F_{BA} is the magnitude of the force.

substitute 350lb for F_{BA} and (\frac{-5i+6k+14k}{16.031}) for U_{BA}.

F_{BA} = 350 x (\frac{-5i+6k+14k}{16.031})

      =-109.2i+131j+305.7k lb

8 0
3 years ago
Calculate the change in length of a Pyrex glass dish (Coefficient of linear expansion for Pyrex is 3 * 10-6 / oC) that is 0.25 m
DIA [1.3K]

9*10^{-5} m

Explanation:

Step 1:

We are given the initial length of the Pyrex glass dish at a particular temperature and need to calculate the change in the length when the temperature changes by 120° C. The coefficient of linear expansion of Pyrex is provided.

Step 2:

Change in length = Coefficient of linear expansion * Change in temperature * Initial length

Step 3:

Coefficient of linear expansion = 3*10^{-6} /°C

Change in temperature = 120°C = 120 K

Initial length = 0.25 m

Step 4:

Change in length = 3*10^{-6} * 120 * 0.25 = 9*10^{-5} m

8 0
4 years ago
If the mass of one object is tripled, and the distance between them is doubled, how does the force of gravity change?
fredd [130]
Force between two object is given by F = Gm1m2/r^2
<span>If the mass of one object is tripled, and the distance between them is doubled,</span>
then F(new) = Gm13m2/(2r)^2 = 3Gm1m2/4r^2 = 3/4 x Gm1m2/r^2 = 3/4 x F
i.e. F(new) = 3/4 multiplied by F.
Therefore, Force is multiplied by 3/4.
8 0
3 years ago
A fireworks shell is accelerated from rest to a velocity of 68.0 m/s over a distance of 0.230 m.
Ugo [173]

Answer:

(A) 10052.2 m/s²

(B)  0.00678 seconds

Explanation:

From the question,

(A) Applying

V² = U²+2as..................... Equation 1

Where V = Final velocity, U = Initial velocity, a = acceleration due to gravity, s = distance.

make a the subject of the  equation

a = (V²-U²)/2s........................ Equation 2

Given: U = 0 m/s( from rest), V = 68 m/s, s = 0.230 m

Substitute these values into equation 2

a = (68²-0²)/(2×0.230)

a = 10052.2 m/s²

(B) Using,

a = (V-U)/t......................... Equation 3

Where t= time.

make t the subject of the equation

t = (V-U)/a......................... Equation 4

Given: V = 68 m/s, U = 0 m/s, a = 10052.2

Substitute into equation 4

t = (68-0)/10052.2

t = 0.00678 seconds

5 0
4 years ago
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