Avagadro's law gives the relationship between volume of gas and number of moles of the gas. When the temperature and pressure are constant, volume is directly proportional to number of moles of gas.

V -volume and n - number of moles of gas.
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
initial number of moles n1 - N
n2 - 2N as the number of moles are doubled
V1 - initial volume - 2.10 L
V2 - final volume - V
substituting the values in the equation

V = 4.20 L
final volume is 4.20 L
Answer:
Mass of PbS = 9.26 g
Explanation:
Data Given :
mass of H₂S = 5.00 g
mass of PbS = ?
Reaction Given:
Pb(CH₃COO)₂ + H₂S ----→ PbS + CH₃COOH
Solution:
Balance the equation:
Pb(CH₃COO)₂ + H₂S ----→ PbS + 2CH₃COOH
Now Look for the number of moles of H₂S and PbS meta
Pb(CH₃COO)₂ + H₂S ----→ PbS + 2CH₃COOH
1 mol 1 mol
So,
1 mole of H₂S combine with excess (unlimited) supply of Pb(CH₃COO)₂ and produce 1 moles of PbS
Now Convert moles to mass for which we have to molar masses of H₂S and PbS
Molar mass of H₂S = 2 + 32 = 43 g/mol
Molar mass of PbS = 31 + 32 = 63 g/mol
Pb(CH₃COO)₂ + H₂S -------→ PbS + 2CH₃COOH
1 mol (34 g/mol) 1 mol (63 g/mol)
34 g 63 g
So,
34 g of H₂S produces 63 grams of PbS.
Now
What mass of silver is produced from 5 g of H₂S
Apply unity formula
34 g of H₂S ≅ 63 g of PbS
5 g of H₂S ≅ X g of PbS
By doing cross multiplication
Mass of PbS = 63 g x 5 g / 34 g
Mass of PbS = 9.26 g