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zhannawk [14.2K]
3 years ago
5

A selectively permeable membrane separates solution a and

Chemistry
1 answer:
Yakvenalex [24]3 years ago
3 0
The water molecules will flow from b to a due to osmosis.

Osmosis is where water molecules will flow from a region of higher water potential to a region of lower water potential, through a selectively permeable membrane.

When the water molecule concentration is higher, it has a higher water potential top. Water potential is the tendency for them to flow to a lower region.

The net movement will stop until both sides of the solution has a same water potential.
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A patient needs to take 625 mg of ibuprofen twice daily. The pills in the bottle are each 250. mg. How many pills does the patie
WINSTONCH [101]
2 and a half
250 x 2 =500
250/2=125
and 125 is a half of 250
so your answer is
2 and a half
5 0
3 years ago
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Calculate the pH of each solution at 25∘C
JulijaS [17]

Answer: pH of HCl =5, HNO3 = 1,

NaOH = 9, KOH = 12

Explanation:

pH = -log [H+ ]

1. 1.0 x 10^-5 M HCl

pH = - log (1.0 x 10^-5)

= 5 - log 1 = 5

2. 0.1 M HNO3

pH = - log (1.0 x 10 ^ -1)

pH = 1 - log 1 = 1

3. 1.0 x 10^-5 NaOH

pOH = - log (1.0 x 10^-5)

pOH = 5 - log 1 = 5

pH + pOH = 14

Therefore , pH = 14 - 5 = 9

4. 0.01 M KOH

pOH = - log ( 1.0 x 10^ -2)

= 2 - log 1 = 2

pH + pOH = 14

Therefore, pH = 14 - 2 = 12

8 0
3 years ago
What's it called when an electron has absorbed alot of energy?​
emmainna [20.7K]

Answer:

Excited state

Explanation:

Excited state is the name of the state when electrons absorb energy and move to a higher energy level.

Hope this helps!

8 0
3 years ago
Some plz help me make mnemonic to helpme remember the oder of the planets​
Iteru [2.4K]

Answer:

My - Mercury

Very- Venus

Excited- Earth

Mother- Mars

Just- Jupiter

Served- Saturn

Us- Uranus

Nachos- Neptune

Explanation:

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3 0
2 years ago
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How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?
Dominik [7]
The grams   of glucose  are  needed  to  prepare  400g  of  a 2.00%(m/m)  glucose  solution  g  is  calculated  as  below

=% m/m =mass  of the solute/mass  of  the  solution  x100

let mass of   solute  be represented  by  y
mass  of solution = 400 g
 % (m/m) = 2% = 2/100

 grams  of  glucose  is  therefore =2/100 =  y/400
by cross  multiplication

100y = 800
divide   both side  by  100

y= 8.0 grams



5 0
3 years ago
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