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3 years ago

A selectively permeable membrane separates solution a and

1 answer:

3 0

The water molecules will flow from b to a due to osmosis.

Osmosis is where water molecules will flow from a region of higher water potential to a region of lower water potential, through a selectively permeable membrane.

When the water molecule concentration is higher, it has a higher water potential top. Water potential is the tendency for them to flow to a lower region.

The net movement will stop until both sides of the solution has a same water potential.

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For heat transfer purposes, a standing man can be modeled as a 30-cm-diameter, 175-cm-long vertical cylinder with both the top a

tigry1 [53]

Answer:

Sgen = 0.0366 W/K

Explanation:

for the body:

∴ Q = - 336 W...rate of heat loss

∴ T surface = 35°C ≅ 308 K

the rate of entropy transfer from the body:

⇒ ΔS = - Q/Ts

for the enviroment:

⇒ ΔS = Q/Te

∴ assuming: T = Tenv = 25°C ≅ 298 K

resulting in a net variation in the universe:

⇒ Sgen = ΔS = Q/Tenviroment - Q/Tsurface = Q(Ts - Te)/Ts*Te

⇒ Sgen = (336( 308-298))/(308×298) = 3360 WK/91784 K² = 0.0366 W/K

3 0

3 years ago

Static, sliding and rolling are types of friction. Please select the best answer from the choices provided

GarryVolchara [31]

The answer is true ^-^

6 0

3 years ago

For the n = 3 electron shell, which of the following quantum numbers are valid? Check all that apply.

stealth61 [152]

Answer:

The valid quantum numbers are l=0, l=-2 and l= 2.

Explanation:

Given that,

n = 3 electron shell

Suppose, the valid quantum numbers are

l = 3

m = 3

l = 0

m = –2

l = –1

m = 2

We know that,

The value of n = 3

Principle quantum number :

Then the principal quantum number is 3. Which is shows the M shell.

So, n = 3

Azimuthal quantum number :

The azimuthal quantum number is l.

$l=0,1,2$

Magnetic quantum number :

The magnetic quantum number is

$m=-2,-1,0,1,2$

Hence, The valid quantum numbers are l=0, l=-2 and l= 2.

7 0

3 years ago

Read 2 more answers

Calculate the energy in joules and calories required to heat 25.0 g of water from 12.5C to 25.7C

Alex Ar [27]

The heat (Q) required to raise the temp of a substance is:Q=m∗Cp∗ΔT where m is the mass of the object (25.0g in this case), Cp is the specific heat capacity of the substance (for water Cp = 1.00cal/gC, or 4.18J/gC,
and Dt is the change in temp.
You'll have to solve this twice, once with the Cp in calories, and once with the Cp in joules.
1380.72 Joules

8 0

2 years ago

Which of the following represents positron emission? Select one: a. 3015P ---> 3014Si + ___ b. 23892U ---> 23490Th + ___ c

xxTIMURxx [149]

The simple trick which one can consider in such problem where it is asked for positron emission is :
When the atomic number goes DOWN by one and mass number remains unchanged, then a positron is emitted.

a. $P^{30}_{15} ----\ \textgreater \ Si^{30}_{14} + e^{0}_{1}^+$

Here the atomic number decreases by one.

Similarly, options b and d are eliminated.

Option c is also not the answer.
For c, Count the atomic number on left side and compare it with right side. You will see it is 9 on left and 8 on right. Atomic no. did go down by 1. But the atomic mass is changed as well.

8 0

3 years ago