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iren2701 [21]
3 years ago
8

Help me guys pls pls pls lutang nako huhuhu help!!!​

Physics
1 answer:
MArishka [77]3 years ago
6 0

Answer:

hejwjeuhsy de la granja de la granja

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Two tiny, spherical water drops, with identical charges of −8.00 ✕ 10^(−17) C, have a center-to-center separation of 2.00 cm.
Damm [24]

Answer:

F=1.4384×10⁻¹⁹N

Explanation:

Given Data

Charge q= -8.00×10⁻¹⁷C

Distance r=2.00 cm=0.02 m

To find

Electrostatic force

Solution

The electrostatic force between between them can be calculated from Coulombs law as

F=\frac{kq^{2} }{r^{2} }

Substitute the given values we get

F=\frac{(8.99*10^{9} )*(-8.00*10^{-17} )^{2} }{(0.02)^{2} }\\ F=1.4384*10^{-19} N

7 0
3 years ago
Car A hits car B (initially at rest and of equal mass) from behind while going 15 m/s Immediately after the collision, car B mov
Mamont248 [21]

Given :

Initial speed of car A is 15 m/s and initial speed of car B is zero.

Final speed of car A is zero and final speed of car B is 10 m/s.

To Find :

What fraction of the initial kinetic energy is lost in the collision.

Solution :

Initial kinetic energy is :

K.E_i = \dfrac{15^2m}{2} + 0\\\\K.E_i = \dfrac{225 m}{2}

Final kinetic energy is :

K.E_f = \dfrac{10^2m}{2} + 0\\\\K.E_f = \dfrac{100m}{2}

Now, fraction of initial kinetic energy loss is :

Loss = \dfrac{\dfrac{225m}{2}-\dfrac{100m}{2}}{\dfrac{100m}{2}}\\\\Loss = \dfrac{125}{100}\\\\Loss = 1.25

Therefore, fraction of initial kinetic energy loss in the collision is 1.25 .

6 0
2 years ago
I love you <br><br><br>Please answer my question :-)
Novay_Z [31]

Answer:

A- Astronomical body

C- Galaxy

D- Comet

B- Moon

Hope this helps you! Have a great day!

6 0
3 years ago
Read 2 more answers
How long will it take you to ride your bike 120 miles if you are riding at 5mph?
lana66690 [7]
If i'm wrong sorry but i think it is 24hrs
4 0
2 years ago
Read 2 more answers
Draw the following vector quantity Using the coordinate system.
DiKsa [7]

The given vectors quantities can be described by their properties of both

magnitude and direction.

  • a. The drawing of the vector extending from point (0, 0) to (190, 0) on the coordinate plane is attached.
  • b. The velocity vector extending from  (0, 0) to (108.76, 50.714) on the coordinate plane is attached.
  • c. The displacement vector extending from (0, 0) to (30·√2, 30·√2) is attached.

Reasons:

a. The magnitude of the vector = 190 N

The direction in which the vector acts = East

Therefore, in vector form, we have;

\vec{F} = 190 × cos(0)·i + 190 × sin(0)·j = 190·i

The vector can be represented by an horizontal line, 190 units long

Coordinate points on the vector = (0, 0) and (190, 0)

The drawing of the vector with the above points using MS Excel is attached.

b. Magnitude of the velocity vector = 120 km/hr. 25° North of east

Solution;

The vector form of the velocity is; \vec{v} = 120 × cos(25)·i + 120×sin(25)·j, which gives;

\vec{v} = 120 × cos(25)·i + 120×sin(25)·j ≈ 108.76·i + 50.714·j

\vec{v} ≈ 108.76·i + 50.714·j

Therefore, points that define the vector are; (0, 0) and (108.76, 50.714)

The drawing of the vector is attached

c. The magnitude of the vector = 60 m

The direction of the vector is southwest = West 45° south

The vector form of the displacement is \vec{d} = 60 × cos(45°)·i + 60 × sin(45°)·j

Which gives;

\vec{d} = 30·√2·i + 30·√2·j

Points on the vector are therefore; (0, 0), and (30·√2, 30·√2)

The drawing of the vector is attached

Learn more about vectors here:

brainly.com/question/10409036

4 0
2 years ago
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