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3 years ago

9

An student in a swimming pool weighs 450 N and in a regular balance out of the swimming pool weighs 700 N. What is the value of

the buoyant force?

1 answer:

rewona [7]3 years ago

7 0

The value of buoyant force is 700-450=300N

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An object with smaller mass and an object with a larger mass have the same kinetic energy. Which object has the higher momentum?

KatRina [158]

Answer:

object with larger mass

Explanation:

the momentum of an object is directly proportional to its mass. larger mass = more momentum

4 0

3 years ago

Read 2 more answers

A spherical capacitor is formed from two concentric spherical conducting shells separated by vacuum. The inner sphere has a radi

Svetlanka [38]

Answer: a) 73.41 10^-12 F; b)4.83* 10^3 N/C; c) 3.66 *10^3 N/C

Explanation: To solve this problem we have to consider the following: The Capacity= Charge/Potential Difference

As we know the capacity is value that depend on the geometry of the capacitor, in our case two concentric spheres.

So Potential Difference between the spheres is given by:

ΔV=- $\int\limits^a_b {E} \, dx$

Where E = k*Q/ r^2

so we have $\int\limits^a_b {K+Q1/r} \, dr$

then

Vb-Va=k*Q(1/b-1/a)=kQ (ab/b-a)

Finally using C=Q/ΔV=ab/(k(b-a))

To caclulate the electric firld we first obtain the charge

Q=ΔV*C=120 V*73.41 10^-12 F=8.8 10^-9 C

so E=KQ/r^2 for both values of r

r=12.8 cm ( in meters)

r2=14.7 cm

E(r1)=4.83* 10^3 N/C

E(r2)=3.66 *10^3 N/C

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3 years ago

Article 5 of the Fundamental Orders of Connecticut is MOST LIKELY related to which idea?

Sauron [17]

Answer:

Option A, Rule of law

Explanation:

The complete question is

Article 5 of the Fundamental Orders of Connecticut is MOST LIKELY related to which idea? A) rule of law B) personal freedom C) individual rights D) limited government

Solution

It is the first colonial constitution and also the first written constitution in America. It was first applicable to the inhabitants and Residents of Windsor, Harteford and Wethersfield

The article V of the Fundamental Orders of Connecticut is subjected to the Courte of Election of the towns. The towns were responsible for maintaining their own form of government through election with the involvement of general public. The 5th article is about the Judicial Department and the process of selection of judges who further governs the city. This abide by law of equality by vesting equal right of choosing the judges.

3 0

3 years ago

Please help on this one somebody? :)

ahrayia [7]

ans D. Substance B has a greater latent heat of vaporization than substance A.

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3 years ago

A 190 g glider on a horizontal, frictionless air track is attached to a fixed ideal spring with force constant 160 N/m. At the i

laiz [17]

(a) Let <em>x</em> be the maximum elongation of the spring. At this point, the glider would have zero velocity and thus zero kinetic energy. The total work <em>W</em> done by the spring on the glider to get it from the given point (4.00 cm from equilibrium) to <em>x</em> is

<em>W</em> = - (1/2 <em>kx</em> ² - 1/2 <em>k</em> (0.0400 m)²)

(note that <em>x</em> > 4.00 cm, and the restoring force of the spring opposes its elongation, so the total work is negative)

By the work-energy theorem, the total work is equal to the change in the glider's kinetic energy as it moves from 4.00 cm from equilibrium to <em>x</em>, so

<em>W</em> = ∆<em>K</em> = 0 - 1/2 <em>m</em> (0.835 m/s)²

Solve for <em>x</em> :

- (1/2 (160 N/m) <em>x</em> ² - 1/2 (160 N/m) (0.0400 m)²) = -1/2 (0.190 kg) (0.835 m/s)²

==> <em>x</em> ≈ 0.0493 m ≈ 4.93 cm

(b) The glider attains its maximum speed at the equilibrium point. The work done by the spring as it is stretched away from equilibrium to the 4.00 cm position is

<em>W</em> = - 1/2 <em>k</em> (0.0400 m)²

If <em>v</em> is the glider's maximum speed, then by the work-energy theorem,

<em>W</em> = ∆<em>K</em> = 1/2 <em>m</em> (0.835 m/s)² - 1/2 <em>mv</em> ²

Solve for <em>v</em> :

- 1/2 (160 N/m) (0.0400 m)² = 1/2 (0.190 kg) (0.835 m/s)² - 1/2 (0.190 kg) <em>v</em> ²

==> <em>v</em> ≈ 1.43 m/s

(c) The angular frequency of the glider's oscillation is

√(<em>k</em>/<em>m</em>) = √((160 N/m) / (0.190 kg)) ≈ 29.0 Hz

3 0

3 years ago