Answer:
1.169s
Explanation:
k = 0.851 M-1s-1
The unit of the rate constant, k tells us this is a second order reaction.
From the question;
Initial Concentration [A]o = 2.01M
Final Concentration [A] = One third of 2.10 = (1/3) * 2.10 = 0.67M
Time = ?
The integrated rate law for second order reactions is given as;
1 / [A] = (1 / [A]o) + kt
Making t subject of interest, we have;
kt = (1 / [A] ) - (1 / [A]o )
t = (1 / [A] ) - (1 / [A]o ) / k
Inserting the values;
t = [ (1 / 0.67 ) - (1 / 2.10) ] / 0.851
t = ( 1.4925 - 0.4975 ) / 0.851
t = 0.995 / 0.851
t = 1.169s
[A] = 0.13073 M ≈ 0.13 M ( 2 s.f)
It introduces a diverse array of bacteria, algae, and invertebrates to the closed marine environment and functions as a superior biological filter
Answer:
the conservation of mass means matter can be created or destroyed, it only changes forms
Explanation:
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From the Rutherford's gold foil experiment one can conclude that nucleus was very small in size, as compared to the atoms. In the experiment Rutherford discovered that, the atom contains a very small nucleus where all of its positive charge of the atom is present.
Answer:
Hi, the question is incomplete. However, the question is about the calculation of volume of a product when the volume of one of the reactants is provided.
9.587 cm^3
Explanation:
The balanced equation for the chemical reaction is shown below:
⇒
In the chemical reaction above, 2 moles of water produced 4 moles of hydrogen fluoride. If 4.8 cm^3 of water were consumed, we can calculated the volume of hydrogen fluoride that would be produced as follow:
Using STP, 1 mole of gas has a volume of 22.4 L
Thus, 4.8 cm^3 = 0.0048 L is equivalent to 2.14*10^-4
since 2 moles of water produced 4 moles of hydrogen fluoride, therefore, 2.14*10^-4 would produced 2*2.14*10^-4 = 4.28*10^-4 moles
we can convert the moles to L by multiplying with 22.4
volume of hydrogen fluoride = 4.28*10^-4 * 22.4 = 0.009587 L = 9.587 cm^3
