Question

for the following reaction: 1 CuO + 1 H2 --> 1 Cu +1H2O, what is the quantity of moles of H2O when there are 240 grams of CuO present?

Answer 1

Considering the reaction stoichiometry, the quantity of moles of H₂O produced is 3.02 moles.

The balanced reaction is:

CuO + H₂ → Cu + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:  

• CuO= 1 mole
• H₂= 1 mole
• Cu= 1 mole
• H₂O= 1 mole

The molar mass of the compounds present in the reaction is:

• CuO= 79.55 g/mole
• H₂= 2 g/mole
• Cu= 63.55 g/mole
• H₂O: 18 g/mole

Then, by reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of mass of each compound participate in the reaction:  

• CuO= 1 mole× 79.55 g/mole= 79.55 grams
• H₂= 1 mole× 2 g/mole= 2 grams
• Cu= 1 mole× 63.55 g/mole= 63.55 grams
• H₂O: 1 mole× 18 g/mole= 18 grams

Then, it is possible to determine the moles of H₂O necessary by the following rule of three:  If by reaction stoichiometry 79.55 grams of CuO produces 1 mole of H₂O, 240 grams of CuO produces how many moles of H₂O?

$molesofH_{2} O=\frac{240 grams of CuOx 1 mole ofH_{2} O }{79.55 grams of CuO}$

moles of H₂O= 3.02 moles

Finally, the quantity of moles of H₂O produced is 3.02 moles.

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