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zhuklara [117]
3 years ago
9

Webb has calculated the percent composition of a compound. How can he check his result?

Chemistry
2 answers:
wel3 years ago
8 0

Answer:

The answer is B

Explanation:

goldenfox [79]3 years ago
7 0

by making sure they are in the lowest ratio. by adding them to see if they total 100. by checking that they are whole-number multiples. by dividing them by the molar mass.

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Two chemical reactions are shown:
Nina [5.8K]

Answer: B

Oxygen acts as oxidator in the first reaction.

Explanation:

At reactant side:

Mg = 0

At product side:

MgO = 0

but Oxygen (O) = -2

Mg + O = 0

Mg + (-2) = 0

Mg - 2 = 0

Mg = 2

Magnesium is oxidized by OXYGEN from zero to +2

Oxygen acts as oxidator in the first reaction.

8 0
3 years ago
Read 2 more answers
An atom with 2 protons 3 neutrons and 2 electrons has a charge of
V125BC [204]

Answer: It has a charge of -2 because it has 2 more electrons than protons meaning it has a negative charge of 2 which is -2. Neutrons don't effect charge.

( +1 +1 -1 -1 -1 -1) = -2

Each proton has a charge of +1 and each electron has -1.

2(1) - 4(1) = -2

Explanation:

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4 0
3 years ago
An atom has 4 protons 4 neutrons, and 4 electrons. This atom has a mass number of
Art [367]

Answer:

16

Explanation:

Hope it helps you

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6 0
3 years ago
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The atomic number is determined only by the number of ________ in the nucleus of an atom. But, in a neutral atom it also represe
sveticcg [70]

Hello!

The atomic number is determined only by the number of protons in the nucleus of an atom. But, in a neutral atom it also represents the number of electrons in the electron cloud.


Neutrons are only important in the nucleus for helping us find atomic weight, which varies as we move along the perodic table and does not always equal the same amount of it's atomic number. Which is why it would not be a suitable answer for the first blank space. Electrons do not work either as they do not exist inside the nucleus but rather outside the atom.

The second space, since it states is in the electron cloud, we can deduct that electrons would be an appropriate answer there.

If you need anymore help feel free to ask, but I hope this answers your question.

5 0
3 years ago
while doing a lab, a student found the density of a piece of pure aluminum to be 2.85 g/cm^3. the accepted value for the density
vagabundo [1.1K]

Answer:

Percent error = 5.6%

Explanation:

Given data:

Measured value of density by students = 2.85 g/cm³

Accepted density of aluminium = 2.70 g/cm³

Percent error = ?

Solution:

Formula:

Percent error = [ Measured value - accepted value / accepted value ]× 100

Now we will put the values in formula:

Percent error = [ 2.85 g/cm³  - 2.70 g/cm³ / 2.70 g/cm³ ]× 100

Percent error = [0.15/2.70 g/cm³ ] × 100

Percent error = 0.056× 100

Percent error = 5.6%

7 0
4 years ago
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