We know that each millimeter contains 10⁻³ meters. Writing this as a ratio:
1 mm : 10⁻³ m
We require a conversion from m³ to mm³, so we must take the cube of the ratio we have made:
1 mm³ = (10⁻³)³ m³
Therefore, the conversion used will be:
(1 mm / 10⁻³ m)³
When we multiply by this conversion, we will get:
32 m³ = 32 x 10⁹ mm³
the answer is Te because O is oxygen.
Answer:
Decreased because the method can not distinguish oxygen from the gas added
Explanation:
Answer:
<u>Balanced equation:</u>

Explanation:
The chemical reaction between Lead(II) Nitrate and potassium carbonate is as follows.


<u>Ionic equation:</u>

Cancel the same ions on the both sides of the reaction.
The net ionic equation is as follows.
