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Musya8 [376]
3 years ago
12

A closed, nonreactive system contains species Aand Bin vapor/liquid equilibrium. Species Ais a very light gas, essentially insol

uble in the liquid phase. The vapor phase contains both species Aand B. Some additional moles of species Bare added to the system, which is then restored to its initial T and P. As a result of the process, does the total number of moles of liquidincrease, decrease, or remain unchanged?
Chemistry
1 answer:
musickatia [10]3 years ago
5 0

Answer:

Remain unchanged.

Explanation:

The total number of moles of liquid remain unchanged as the some moles of species B are added to the system because specie B that is added in the liquid phase is again restored after addition. If the specie B did not restored after addition to the liquid phase so the total number of moles increases in the liquid phase so that's why we can say that the liquid phase remain unchanged.

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Iron is ___<br> A, FE<br> B,CU<br> C,K<br> D, CA
Fiesta28 [93]

<em>Answer:</em>

<em>Ello mate ! the answer is super simple it's option "A" Fe</em>

<em>Explanation:</em>

<em>Iron is a chemical element with symbol</em><em> "Fe"</em><em> and atomic number 26. It is a type of metal, that belongs to the first transition series and group 8 of the periodic table. It is by mass the most common element on Earth, forming much of Earth's outer and inner core.</em>

5 0
4 years ago
Read 2 more answers
Determine what type of compound is shown below:
34kurt

Answer:

Polar

Explanation:

Methanol is not electrostatic

It's not metallic as it has no metals in it

It's not ionic as coordinate bonding is made.

It's polar as a lone pair is present over OH-

3 0
2 years ago
Elements in the same group have _____.
tresset_1 [31]

Answer:

Element in the same group have similar chemical properties.

8 0
3 years ago
Read 2 more answers
How do you write the balanced equation for strontium hydroxide and zirconium (I) perchlorate
Andrei [34K]

The law of conservation of mass states that the mass of a system must remain constant everytime, it can neither be created or destroyed. This means the number of atoms of each element on reactant side must equal the number of atoms of each element on product side.

First we figure out the chemical formula for each compound by taking advantage of oxidation states which are able to tell us whether an element will lose or gain an electron

Strontium hydroxide?

Sr is an alkaline earth metal which has 2 valence electrons that when both are lost it has an oxidation state of +2. Since we know the hydroxide ion has a charge of -1, -_{OH}, Then two -_{OH} are needed to form compound, hence we have SrOH_2

zirconium (I) perchlorate?

The oxidation state of zirconium is +1 since it is stated that we have zirconium(I). Converserly, perchlorate has a -1 charge which further proves that zirconium has a +1 oxidation state

The product would have a strontium diperchlorate because we know from earlier that Sr has a +2 oxidation state, and we would also have ZrOH because Zr has a +1 oxidation state and -_{OH} has a -1 charge

The unbalanced equation with all chemicals formulas would be

SrOH_2_(s) + ZrClO^{-} _4(aq) ==> Sr(ClO^{-} _4)_2(aq) + ZrOH(aq)

Using the law of conservation of mass, it is clear that there is 1 molecule of ClO^{-} _4 on reactant side as compared to 2 molecules of ClO^{-} _4 on product side. On the other hand, the are 2 molecules of -_{OH} on reactant side and 1 molecule of  -_{OH} on product side. To balance we add a coefficient of 2 on ZrClO_4 and a coefficient of 2 on ZrOH,

SrOH_2_(s) + 2ZrClO_4_(aq) ==> Sr(ClO_4)_2_(aq) + 2ZrOH(aq).

7 0
3 years ago
Determine the value of Kc for the following reaction if the equilibrium concentrations are as follows: [H2]eq = 0.14 M, [Cl2]eq
pentagon [3]

Question:

A) 12

B) 29

C) 2.1 × 10⁻²

D) 8.7 × 10⁻²

E) 47

Answer:

The correct option is;

E) 47

Explanation:

Kc, which is the equilibrium constant of a chemical reaction is derived by finding the ratio between the product of the equilibrium concentration of the product raised to their respective coefficients to the product of the equilibrium concentration of the reactants also raised to their respective coefficients.

Here we have;

[H₂] = 0.14 M

[Cl₂] = 0.39 M

[HCl] = 1.6

The reaction is given as follows;

H₂ (g) + Cl₂ (g) ⇄ 2HCl (g)

The formula for Kc is given as follows;

Kc = \frac{[HCl]^2}{[H_2][Cl_2]} = \frac{1.6^2}{0.14 \times 0.39}  = 46.886

Therefore, the Kc for the reaction is approximately equal to 47.

3 0
3 years ago
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