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Goryan [66]
3 years ago
15

Another name for a load-center distribution system is a A. primary radial system. B. complex radial system. C. split-radial syst

em. D. dual-radial system.
Engineering
1 answer:
meriva3 years ago
3 0

Answer:

A

Explanation:

Primary radial system

You might be interested in
Given the latent heat of fusion (melting) and the latent heat of vaporisation for water are Δhs = 333.2 kJ/kg and Δhv = 2257 kJ/
kap26 [50]

Answer:

C)185,500 KJ

Explanation:

Given that

Latent heat fusion = 333.23 KJ/kg

Latent heat vaporisation = 333.23 KJ/kg

Mass of ice = 100 kg

Mass of water = 40 kg

Mass of vapor=60 kg

Ice at 0°C ,first it will take latent heat of vaporisation and remain at constant temperature 0°C and it will convert in to water.After this water which at 0°C will take sensible heat and gets heat up to 100°C.After that at 100°C vapor will take heat as heat of  vaporisation .

Sensible heat for water Q

Q=mC_p\Delta T

For water

C_p=4.178\ KJ/Kg.K

Q=4.178 x 40 x 100 KJ

Q=16,712 KJ

So total heat

Total heat =100 x 333.23+16,712 + 60 x 2257 KJ

Total heat =185,455 KJ

Approx Total heat = 185,500 KJ

So the answer C is correct.

8 0
4 years ago
Explain what a stress-concentration is and how it can be accounted for in the design and analysis of a structural component. Be
Mama L [17]

Answer:

Stress-concentration

        In the machine component the stress become concentrate at the point a particular point and due to this crack formation takes places and after some time some the machine component become fails.High stress concentration means high stress at that point.

It is very important in the design point of view because we have to find out where stress concentration is high and needs to take proper factor of safety to avoid the failure of the machine component.Generally at sharp corner,sudden change and complex shapes stress concentration is high.

3 0
3 years ago
the hoop is cast on the rough surface such that it has an angular velocity w=4rad/s and an angular acceleration a=5rad/s^2. also
IgorLugansk [536]

Given Information:

Angular velocity = ω = 4 rad/s

Angular acceleration = α = 5 rad/s²

Center deceleration = a₀ = 2 m/s

Required Information:

Acceleration of point A at this instant = ?

Answer:

Acceleration of point A at this instant = 5.94 m/s²

Explanation:

Refer to the attached diagram of the question,

The acceleration of point A is given by

a = a₀ + rα - rω²

Where r is the radial distance between the center and point A, a₀ is the deceleration of center, α is the angular acceleration and ω is the angular velocity.

a = -2i + 0.3j*5k - 0.3j*4²

a = -2i + 1.5(j*k) - 0.3j*16

a = -2i + 1.5(-i) - 4.8j

a = -2i - 1.5i - 4.8j

a = -3.5i - 4.8j

The magnitude of acceleration vector is

a = √(-3.5)² + (-4.8)²

a = √35.29

a = 5.94 m/s²

Therefore, the acceleration of point A is 5.94 m/s²

The angle is given by

θ = tan⁻¹(y/x)

θ = tan⁻¹(-4.8/-3.5)

θ = 53.9°

7 0
4 years ago
Multiply each element in origList with the corresponding value in offsetAmount. Print each product followed by a space.Ex: If or
n200080 [17]

Answer:

Here is the JAVA program:  

import java.util.Scanner; // to take input from user

public class VectorElementOperations {

public static void main(String[] args) {

final int NUM_VALS = 4; // size is fixed that is 4 and assigned to NUM_VALS

int[] origList = new int[NUM_VALS];

int[] offsetAmount = new int[NUM_VALS];

int i;

//two lists origList[] and offsetAmount[] are assigned values

origList[0] = 20;

origList[1] = 30;

origList[2] = 40;

origList[3] = 50;

offsetAmount[0] = 4;

offsetAmount[1] = 6;

offsetAmount[2] = 2;

offsetAmount[3] = 8;

String product=""; // product variable to store the product of 2 lists

for(i = 0; i <= origList.length - 1; i++){

/* loop starts with i at 0th position or index and ends when the end of the origList is reached */

/* multiples each element of origList to corresponding element of offsetAmount and stores result in the form of character string in product*/

   product+= Integer.toString(origList[i] *= offsetAmount[i]) + " ";  }

 System.out.println(product); }}   //displays the product of both lists

Output:

80 180 80 400

Explanation:

If you want to print the product of origList with corresponding value in offsetAmount in vertical form you can do this in the following way:

import java.util.Scanner;

public class VectorElementOperations {

public static void main(String[] args) {

final int NUM_VALS = 4;

int[] origList = new int[NUM_VALS];

int[] offsetAmount = new int[NUM_VALS];

int i;

origList[0] = 20;

origList[1] = 30;

origList[2] = 40;

origList[3] = 50;

offsetAmount[0] = 4;

offsetAmount[1] = 6;

offsetAmount[2] = 2;

offsetAmount[3] = 8;

for(i = 0; i <= origList.length - 1; i++){

 origList[i] *= offsetAmount[i];

System.out.println(origList[i]); } }}

Output:

80                                                                                                                            

180                                                                                                                          

80                                                                                                                            

400

The program along with the output is attached as screenshot with the input given in the example.

8 0
3 years ago
The atmosphere is divided into different layers, each with a different function. The stratosphere contains the ozone (O3).
tangare [24]

Answer:

a) At about 15 to 35 km from the Earth

b) It helps to absorb most of the ultraviolet rays from the sun, that is otherwise too dangerous here on Earth.

c) The depletion of the ozone layer is due to free radical catalysts, like nitric oxide (NO), nitrous oxide (N2O), hydroxyl (OH), but majorly due to atomic chlorine (Cl), and atomic bromine (Br) finding their way up to the the ozone layer.

d) The refrigeration processes and the aerosol aligned industrial processes, are the major culprits.

Explanation:

a) The ozone layer is lies in the lower portion of the stratosphere, from an height of about 15 to 35 kilometers from the surface of the Earth.

b) The ozone layer contains a large portion of ozone, a molecule of oxygen containing three oxygen atom bonded together. This ozone is created at this level by the action of ultraviolet radiation on an ordinary oxygen molecule, splitting it into two oxygen atom. Each of this oxygen atom then proceed to combine with another ordinary oxygen molecule, to form an ozone molecule. The ozone at this layer absorbs a large portion of the ultraviolet radiation from the sun.

c) The depletion of the ozone layer is due to the presence of some radical, that are able to survive up to the level of the ozone layer. At this level, ultraviolet radiation causes these these radicals to dissociate to give free bromine and chlorine mostly. This chlorine and bromine molecules breaks down the ozone molecules.

d) The various industrial processes includes refrigeration, and the aerosol industries that majorly releases the chlorofluorocarbons (CFCs) and bromofluorocarbons, which are the main culprits of ozone depletion.

5 0
3 years ago
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