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Ket [755]
3 years ago
6

A distillation column with a partial reboiler and a total condenser is being used to separate a mixture of benzene, toluene, and

cumene. The feed is 40 mol% benzene, 30 mol% toluene and 30 mol% cumene. The feed is input as a saturated vapor. We desire 99% recovery of the toluene in the bottoms and 98% recovery of the benzene in the distillate. The reflux is returned as a saturated liquid, and CMO can be assumed. Equilibrium can be represented as constant relative volatilities. Choosing toluene as the reference component, ?benzene-toluene = 2.25 and ?cumene-toluene = 0.210. Use the Fenske equation to find the number of equilibrium stages required at total reflux and the recovery fraction of cumene in the bottoms. b. For the distillation problem given in part a, find the minimum reflux ratio by use of the Underwood equations. Use a basis of 100 moles of feed/h. Clearly state your assumptions. d. For L/D = 1.25(L/D)min , find the total number of equilibrium stages required for the distillation problem presented in parts a and b. Use the Gilliland correlation. Estimate the optimum feed plate location.

Engineering
1 answer:
marshall27 [118]3 years ago
7 0

Answer:

See attached pictures.

Explanation:

Hello,

In this case, considering the given information and that the feed is a saturated liquid, the solution is shown on the attached pictures with the proper information and procedure.

Best regards.

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Snoopy is inflated for the Macy’s Thanksgiving parade with 50,000 L of He at 25 oC and 1.2 atm. What is the percent decrease in
Dvinal [7]

Answer:

D.V.= - 1.34 %

Explanation:

Given that

V₁=50,000 L

T₁=25⁰C = 273 + 25 K =298 K

The final temperature ,T₂= 25 - 4 ⁰C = 21 ⁰C

T₂ = 21 + 273 K= 294 K

We know that for constant pressure process

V_2=\dfrac{T_2}{T_1}\times V_1

V_2=\dfrac{294}{298}\times 50000\ L

V₂=49328.85 L

The percent decrease in the volume is given as

D.V.=\dfrac{49328.85-50000}{50000}\times 100

D.V.= - 1.34 %

5 0
4 years ago
If a plus sight of 12.03 ft is taken on BM A, elevation 312.547 ft, and a minus sight of 5.43 ft is read on point X, calculate t
DochEvi [55]

Answer:

Therefore, height of instrument is 324.577 ft

Therefore, elevation of point x is 330 m

Explanation:

Given that

Plus sight on BM = 12.03 ft

Minus sight is = 5.43 ft

Elevation = 312.547 ft

Height of instrument is H.I

H.I = elevation on bench mark + plus sight

    =  312.547 + 12.03 = 324.577 ft

Therefore, height of instrument is 324.577 ft

Elevation at point x is = H.I - minus sight

                                    = 324.577 - (- 5.43)

                                     = 330.00 m

Therefore, elevation of point x is 330 m

3 0
4 years ago
A circular bar is 800mm in length and 32mm in diameter. The bar is made from a material with a modulus of elasticity E = 150 GPa
Yuki888 [10]

Answer:

For any material if ∈ is the axial strain then the lateral strain is given by -μ∈ is the lateral strain in the object

Where,

μ is the poisson's ratio of the material

The longitudinal strain is calculated as follows

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Thus the lateral strain becomes

\varepsilon _{lateral}=-\mu\varepsilon _{axial}\\\\\varepsilon _{lateral}=-0.27\times 8.75\times 10^{-4}=-2.36\times 10^{-4}

now by definition of lateral strain we have

\varepsilon _{lateral}=\frac{\Delta diameter}{diameter_{original}}\\\\\Rightarrow \Delta Diameter=-2.36\times 10^{-4}\times 32=-7.56\times 10^{-3}\\\\D_{f}-D_{i}=-7.56\times 10^{-3}\\\\D_{f}=32-7.56\times 10^{-3}=31.992mm

By hookes law the stress developed due to the given strain is given by

\sigma =\varepsilon _{axial}E

Applying values we get

\sigma =8.75\times 10^{-4}\times 150\times 10^{9}\\\\\sigma =131.25MPa

Thus the force is calculated as

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nika2105 [10]

Answer:

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Explanation:

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